Answer:
y = 0.125x + -1.375
Step-by-step explanation:
You can try and use desmos.com to help you graph these 2 points. My algebra teacher recommended it if you don't have a physical graphing calculator!
Answer:
<em>1885.5 m^3 of water</em>
<em></em>
Step-by-step explanation:
I'll assume this is the complete question
<em>Lauren has an above-ground pool. To keep the pool's skimmer working well, the water level must be 4 inches from the top of the pool. When the pool is filled to this recommended level, approximately how many cubic feet of water will it contain? Use π = 3.14
</em>
<u><em>The pool forms</em></u><em> a cylinder with a radius of 12 feet and a height of 4.5 feet.</em>
<em></em>
height of pool = 4.5 ft
radius of pool
= 12 ft
height of water is 4 inches below pool top
<em>12 inches make 1 ft</em>
4 inches = 4/12 ft = 0.33 ft
Therefore, height of water = 4.5 - 0.33 = 4.17 ft
<em>volume of the water in this section of the cylinder will be equal to the volume of the cylinder formed</em>
volume of cylinder formed by the water = volume of water = π
h
volume = 3.14 x
x 4.17 = <em>1885.5 m^3 of water</em>
Answer:
a) 30.726m/s and b) 5.5549s
Step-by-step explanation:
a.) What was Chris Huber’s speed in meters per second(m/s)?
Given the distance and time, the formula to obtain the speed is
.
Applying this to our problem we have that
.
So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.
b) What was Whittingham’s time through the 200 m?
In a) we stated that
. This formula implies that
.
First, observer that
.
Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, 
Then, applying 1) we have that

So, Sam Whittingham’s time through the 200 m was 5.5549s.