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Vera_Pavlovna [14]
3 years ago
9

Please help!

Mathematics
1 answer:
svetlana [45]3 years ago
8 0

Answer:

$4,425.7

Step-by-step explanation:

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Write an equation of the line that passes through a pair of points (-5, -2) (3, -1)
Bess [88]

Answer:

y = 0.125x + -1.375

Step-by-step explanation:

You can try and use desmos.com to help you graph these 2 points. My algebra teacher recommended it if you don't have a physical graphing calculator!

5 0
3 years ago
Factor 2x^2 + 7x + 3
Vlad1618 [11]

Answer: (x - 3) (2x-1)

8 0
3 years ago
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Lauren has an above-ground pool. To keep the pool's skimmer working well, the water level must be 4 inches from the top of the p
KIM [24]

Answer:

<em>1885.5 m^3 of water</em>

<em></em>

Step-by-step explanation:

I'll assume this is the complete question

<em>Lauren has an above-ground pool. To keep the pool's skimmer working well, the water level must be 4 inches from the top of the pool. When the pool is filled to this recommended level, approximately how many cubic feet of water will it contain? Use π = 3.14 </em>

<u><em>The pool forms</em></u><em> a cylinder with a radius of 12 feet and a height of 4.5 feet.</em>

<em></em>

height of pool = 4.5 ft

radius of pool12^{2} = 12 ft

height of water is 4 inches below pool top

<em>12 inches make 1 ft</em>

4 inches = 4/12 ft = 0.33 ft

Therefore, height of water = 4.5 - 0.33 = 4.17 ft

<em>volume of the water in this section of the cylinder will be equal to the volume of the cylinder formed</em>

volume of cylinder formed by the water = volume of water = πr^{2}h

volume = 3.14  x 12^{2} x 4.17 = <em>1885.5 m^3 of water</em>

3 0
3 years ago
The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st
Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

v=\frac{d}{t}.

Applying this to our problem we have that

v=\frac{200m}{6.509s}= 30.726m/s.

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that v=\frac{d}{t}. This formula implies that

  1. t=\frac{d}{v}.

First, observer that 19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s.

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.

Then, applying 1) we have that

t=\frac{200m}{36.003m/s}=5.5549s.

So, Sam Whittingham’s time through the 200 m was 5.5549s.

5 0
3 years ago
Can somebody help me with this problem .. I’ll really appreciate it .
Ira Lisetskai [31]

Answer:

4(4x+3)=19x+9-3x+3

4*4x  4*4 =19x+9-3x+3

16x+12= 16x+12

12=12

8 0
3 years ago
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