On Friday, Beth will most likely do 39 sit ups. Every day she is doing an extra 6 sit ups.... Thursday would be 33 sit ups and Friday would be 39 sit ups.
Based on the given description above, I have analyzed it and come up with a solution to get the probability if in a random sample of 25 students from this said group and the average height is between 73 and 75 inches. So if you calculate it, it will be like this:
<span>2P(Z<2)−1</span>
To find the probability of Z, use the normal distribution table.
The value for Z being less than 2 is 0.9772.
The final result is then<span><span>2(0.9772)−1=0.9544
Hope this is the answer that you are looking for.</span></span>
Answer:
Step-by-step explanation:
to be honest I'm not sure how
Answer:
Step-by-step explanation:
The given equality is
Take the term 
to the left hand side. This means the term 
will be divided by
Now since both the numerator and denominator have negative sign the value of fraction will be positive.
Now 
and 
So, the missing factor
