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1 year ago

Scientific process how can a casual question be answered 3 hypotheses water experiment

Chemistry

1 answer:

Vlad1618 [11]1 year ago

3 0

There are 3 experiments which helps to under water evaporation system.

Both the temperature of the air surrounding the water and the rate of evaporation increased.
In the second experiment, we observed an increase in air flow around the water, and this time, the rate of evaporation increased as well.
In the third and final experiment, we observed an increase in the amount of light in the room, and this time, the rate of evaporation increased as well.
Because the kinetic energy of a substance can be measured by its temperature, increasing in the temperature or kinetic energy of the air around water will also increase the kinetic energy of the water, which will increase the rate of evaporation.
It's crucial to have good air flow since it drives water droplets in the air away from you, reducing the amount of humidity in the region. Because there will then be space for the evaporated air or space for the evaporated water to flow into the air, it will then be simpler for the water to really evaporate.
Water in the presence of sunlight is given extra energy, which increases evaporation.

Learn more about Evaporation here:

brainly.com/question/24258

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Describe the relationship between the radius of a cation and that of the atom from which it is formed. a. cations are much small

koban [17]

<h3><u>Answer;</u></h3>

Cations are much smaller than their corresponding parent

<h3><u>Explanation;</u></h3>

Parent atom has more electrons and thus the effective nuclear charge on each electron is less.
When a cation is formed electron(s) is/are lost. Thus the effective nuclear charge or simply put, the attraction of the nucleus towards the electrons increases. Therefore, due to greater pull, the nucleus pulls the shells towards it, there by reducing the size, which makes cations smaller than their corresponding parent.

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2 years ago

The walls in your home have 25mm of expanded polystyrene (R-value 3.96) and 25mm of rigid urethane foam (R-value 7.50). What is

Finger [1]

Answer:

3.6 per inch

EPS insulation features an average r-value of 3.6 per inch.

In addition to providing energy efficiency, EPS without film facers has a perm rating of up to 5.0.

Explanation:

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7 0

3 years ago

In the following reaction, C6H6)? 2C6H6 + 15O2 12CO2 + 6H2O,

shepuryov [24]

The answer is 27.92g . working is shown in the picture above.

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3 years ago

Which pH corresponds to the equivalence point for the graph below?

Evgen [1.6K]

Answer 10
Explication nose

7 0

2 years ago

Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate

uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: $m_{(AcO)_2Cu} = 0.972 g$

Volume of the sodium chromate solution: $V_{Na_2CrO_4} = 150.0 mL$

Molarity of the sodium chromate solution: $c_{Na_2CrO_4} = 0.0400 M$

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

$(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)$

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

$n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol$

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

$n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol$

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

$Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)$

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

$n_{(AcO)_2Cu} = 0.0053515 mol$

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

$n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol$

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

$c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M$

8 0

3 years ago