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1 year ago

Scientific process how can a casual question be answered 3 hypotheses water experiment

Chemistry

1 answer:

Vlad1618 [11]1 year ago

3 0

There are 3 experiments which helps to under water evaporation system.

Both the temperature of the air surrounding the water and the rate of evaporation increased.
In the second experiment, we observed an increase in air flow around the water, and this time, the rate of evaporation increased as well.
In the third and final experiment, we observed an increase in the amount of light in the room, and this time, the rate of evaporation increased as well.
Because the kinetic energy of a substance can be measured by its temperature, increasing in the temperature or kinetic energy of the air around water will also increase the kinetic energy of the water, which will increase the rate of evaporation.
It's crucial to have good air flow since it drives water droplets in the air away from you, reducing the amount of humidity in the region. Because there will then be space for the evaporated air or space for the evaporated water to flow into the air, it will then be simpler for the water to really evaporate.
Water in the presence of sunlight is given extra energy, which increases evaporation.

Learn more about Evaporation here:

brainly.com/question/24258

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Determine the pH of a 2.8 ×10−4 M solution<br> of Ca(OH)2.

shepuryov [24]

Answer:

pH = 10.75

Explanation:

To solve this problem, we must find the molarity of [OH⁻]. With the molarity we can find the pOH = -log[OH⁻]

Using the equation:

pH = 14 - pOH

We can find the pH of the solution.

The molarity of Ca(OH)₂ is 2.8x10⁻⁴M, as there are 2 moles of OH⁻ in 1 mole of Ca(OH)₂, the molarity of [OH⁻] is 2*2.8x10⁻⁴M = 5.6x10⁻⁴M

pOH is

pOH = -log 5.6x10⁻⁴M

pOH = 3.25

pH = 14-pOH

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3 years ago

What effect does cutting down forests have on the carbon dioxide levels in the atmosphere?

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2 years ago

CaO + H2O -> Ca(OH)2

yawa3891 [41]

The % yield of Ca(OH)₂ : 62.98%

<h3>Further eplanation </h3>

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

Reaction

CaO + H₂O ⇒ Ca(OH)₂

mass CaO= 4.2 g

mol CaO(MW=56,0774 g/mol) :

$\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{4.2}{56,0774 g/mol}\\\\mol=0.075$

mol Ca(OH)₂ based on mol CaO

mol ratio CaO : Ca(OH)₂,= 1 : 1, so mol Ca(OH)₂ = 0.075

mass Ca(OH)₂(MW=74,093 g/mol) ⇒ theoretical

$\tt mass=mol\times MW\\\\mass=0.075\times 74,093 g/mol\\\\mass=5.557~g$

% yield :

$\tt =\dfrac{actual}{theoretical}\times 100\%\\\\=\dfrac{3.5}{5.557}\times 100\%\\\\=62.98\%$

8 0

2 years ago

Which type of radioactive decay occurs in the following reaction?

ella [17]

This one is beta decay (the -1 subscript tells us that)

7 0

3 years ago

Read 2 more answers

For the reaction 2 NO(g) + 2 H2(g) => N2(g) + 2 H2O(g) the following data were collected. What is the rate law for this react

harkovskaia [24]

<u>Answer:</u> The rate law expression for the given reaction is written below.

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$2NO(g)+2H_2(g)\rightarrow N_2(g)+2H_2O(g)$

Rate law expression for the reaction:

$\text{Rate}=k[NO]^2[H_2]^2$

Hence, the rate law expression for the given reaction is written above.

5 0

3 years ago