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Step2247 [10]
3 years ago
13

You have a nightlight plugged into an outlet in the hallway, which uses 3.5 watts when plugged in. If the house circuit provides

120.0 volts, wh
is the current through this bulb?

A. 420 amps

B.

0.029 amps

C.

34 amps

D.

0.0083 amps
Physics
1 answer:
marusya05 [52]3 years ago
6 0

Answer:

I = 0.029 A

Explanation:

It is given that,

Power of hallway is 3.5 watts

The  house circuit provides 120 volts

We need to find the current through this bulb. The power of electric bulb is given by :

P=VI

I=\dfrac{P}{V}\\\\I=\dfrac{3.5}{120}\\\\I=0.029\ A

So, the electric current is 0.029 A.

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What cities (more than 1) has many fronts
Arisa [49]
Chattanooga - Chatype, London - Johnston, Berlin - BMF Change, Milan - Milano City, Eindhoven - Eindhoven, Stockholm - Stockholm Type, Minneapolis, and St. Paul - Twin. 
6 0
3 years ago
When converted to a household measurement, 9 kilograms is approximately equal to a
Evgen [1.6K]

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8lbs

3 0
3 years ago
The moon's mass is 7.34x10-kg and it is 3.8x10m away from earth. Calculate the gravitational force of attraction between earth a
Nana76 [90]
Again I think you did not give the right constants. So I would use the correct constants for mass of moon and distance from earth to moon.

<span>The formula for force of attraction between any two bodies in the universe
F  =  GMm / r^2.      (Newton's Universal law of Gravitation).

G = Universal gravitational constant, G = 6.67 * 10 ^ -11  Nm^2 / kg^2.
M = Mass of Earth. = 5.97 x 10^24 kg.
m = mass of moon = 7.34 x 10^22  kg.
r = distance apart, between centers = in this case it is the distance from Earth to the Moon
   = 3.8 x 10^8 m.

(Sorry I could not assume with the values you gave, they are wrong, and if we use them we would be insulting Physics).


So F = ((6.67 * 10 ^ -11)*(5.97 x 10^24)*(7.34 * 10^22)) / (3.8 x 10^8)^2.
  Punch it all up in your calculator.
 
I used a Casio 991 calculator, it should be one of the best in the world.Really lovely calculator, that has helped me a lot in computations like this. I am thankful for the Calculator.

F = 2.0240 * 10^ 20 N.
So that's our answer.
Hurray!!</span>




8 0
4 years ago
Read 2 more answers
39 g aluminum spoon (specific heat 0.904 J/g·°C) at 24°C is placed in 166 mL (166 g) of coffee at 83°C and the temperature of th
tatuchka [14]

<u>Answer:</u> The final temperature of the solution is 80.14^oC

<u>Explanation:</u>

The amount of heat released by coffee will be absorbed by aluminium spoon.

Thus, \text{heat}_{absorbed}=\text{heat}_{released}

To calculate the amount of heat released or absorbed, we use the equation:  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

Also,

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]    ..........(1)

where,

q = heat absorbed or released

m_1 = mass of aluminium = 39 g

m_2 = mass of coffee = 166 g

T_{final} = final temperature = ?

T_1 = temperature of aluminium = 24^oC

T_2 = temperature of coffee = 83^oC

c_1 = specific heat of aluminium = 0.904J/g^oC

c_2 = specific heat of coffee= 4.1801J/g^oC

Putting all the values in equation 1, we get:

39\times 0.904\times (T_{final}-24)=-[166\times 4.1801\times (T_{final}-83)]

T_{final}=80.14^oC

Hence, the final temperature of the solution is 80.14^oC

4 0
4 years ago
1. Is this circuit SERIES or PARALLEL?
Setler79 [48]

Answer:

Series

Explanation:

Because I listen to my science teacher

3 0
3 years ago
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