Answer:
Explanation:
To calculate the force we need to use this equation
where L is the total length of the wire
So in this case the small element of current is
Because x is the direction of the current flow.
As is said in the problem B is such that
so to use the equation above we first calculate the following cross product:
so the force:
So here we use the fact that B=0 in any point of the x axis that is not , that means that we only need to do the integration between a very short distant behind the point and a very short distant after that point, meaning:
so is the same as evaluating at
that is:
Answer:
1. Current in the circuit; 1.2 Amps
See attached image for the circuit.
2. Equivalent resistor = 3 Ω
I = 0.3 amps
Potential difference across the battery terminals is: 0.9 V
Explanation:
Part 1.
The internal resistance of 2 ohms is simply added to the circuit in series as shown in the attached image.
Since now we have two resistances in series (2 ohms and 3 ohms) the total of this series combination is 5 ohms. Using Ohm's law, we can derive the current running through the circuit:
Part 2.
Now we have a 1.5 V battery with a 2 ohm internal resistance, connected to two identical 6 ohm resistors.
a. The equivalent resistance presented by the two resistors in parallel:
b. Now the circuit can be represented by a 2 ohm resistor (internal battery resistance) plus a 3 ohm parallel equivalent resistor in series. That is a 5 ohm total resistance. Then Ohm's law becomes:
c. The potential difference across the battery terminals must be the battery's EMF minus the potential drop in its internal resistance:
Answer:
Amplitude is a measure of the size of sound waves. It depends on the amount of energy that started the waves. Greater amplitude waves have more energy and greater intensity, so they sound louder. The same amount of energy is spread over a greater area, so the intensity and loudness of the sound is less.
Explanation:
a mechanical wave is a wave that is an oscillation of matter, and therefore transfers energy through a medium. while waves can move over long distances, the movement of medium transmission-the material- is limited. again, the oscillating material does not move far away from its initial equilibrium position ;)
<u>Astronauts are not weightless during either launch or return to Earth.</u>
<u></u>
<h3>
Brief explanation</h3>
Astronauts become weightless when they stop accelerating. Basically that means when the engines cut out and they begin to coast in orbit. They will remain “weightless” for as long as they are in orbit. To get out of orbit, they have to decelerate (i.e. Accelerate in the opposite direction) and so they begin to feel a force that feels very much like gravity as they are falling back to Earth.
One of the cool things is that you can't tell the difference between gravity and acceleration. They're the same thing as far as your body is concerned. Einstein used a variety of somewhat related thought experiments while he has working out the details of the special theory of relativity.
Hence, with this explanation , we can conclude that astronauts are not weightless during either launch or return to Earth.
Learn more about astronauts being weightless
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