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vfiekz [6]
3 years ago
10

UPHILL, MORE ENGINE POWER WILL BE NEEDED TO OVERCOME THE EFFECTS OF;

Physics
1 answer:
posledela3 years ago
7 0

Answer: Its The Force Of Gravity

I hope this helps :)

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If one of the manual transmission's shafts is found to have not enough free play, then a thorough inspection must be performed t
frosja888 [35]

Answer:

False

Explanation:

4 0
3 years ago
The volume of the moon is about 33% of the volume of the earth.true or false
stealth61 [152]
The moons volume is that of 2 percent of the earth.
4 0
3 years ago
Read 2 more answers
A parallel plate air capacitor has a capacitance of 10 to the power -9. What potential difference is required for a charge of 5×
Maurinko [17]

The potential difference across the capacitor is 5 × 10∧4 volts and the energy stored in it is 1. 25 Joules

<h3>What is the energy in a capacitor?</h3>

The energy stored in a capacitor is an electrostatic potential energy.

It is related to the charge(Q) and voltage (V) between the capacitor plates.

It is represented as 'U'.

<h3>How to determine the potential difference</h3>

Formula:

Potential difference, V is the ratio of the charge to the capacitance of a capacitor.

It is calculated using:

V = Q ÷ C

Where Q = charge 5 × 10∧-5C and C = capacitance 10∧-9

Substitute the values into the equation

Potential difference, V = 5 × 10∧-5 ÷  10∧-9 = 5 × 10∧4 volts

<h3>How to determine the energy stored</h3>

Formula:

Energy, U = 1 ÷ 2 (QV)

Where Q= charge and V = potential difference across the capacitor

Energy, U = 1 ÷ 2 ( 5 × 10∧-5 × 5 × 10∧4)

= 0.5 × 25 × 10∧-1

= 0.5 × 2.5

= 1. 25 Joules

Therefore, the potential difference across the capacitor is 5 × 10∧4 volts and the energy stored in it is 1. 25 Joules

Learn more about capacitance here:

brainly.com/question/14883923

#SPJ1

6 0
2 years ago
A capacitor consists of two parallel plates, each with an area of 17.0 cm2 , separated by a distance of 0.150 cm . The material
Llana [10]

Answer:

a) C = 40.138\,pF, b) q = 16.056\,nC, c) U = 3.212\,\mu J

Explanation:

a) The capacitance of two parallel plates capacitor with dielectric is given by the following expression:

C = K\cdot \epsilon_{o}\cdot \frac{A}{d}

Where:

K - Dielectric constant.

\epsilon_{o} - Vaccum permitivity.

A - Plate area.

d - Distance between plates.

Hence, the capacitance of the system is:

C = (4.00)\cdot (8.854\times 10^{-12}\,\frac{F}{m} )\cdot \left(\frac{17\times 10^{-4}\,m^{2}}{0.150\times 10^{-2}\,m}\right)

C = 4.014\cdot 10^{-11}\,F

C = 40.138\,pF

b) The charge can be found by using the definition of capacitance:

q = C\cdot V_{batt}

q = (4.014\times 10^{-11}\,F)\cdot (400\,V)

q = 1.606\times 10^{-8}\,C

q = 16.056\,nC

c) The energy stored in the charged capacitor is:

U=\frac{1}{2}\cdot Q\cdot V_{batt}

U=\frac{1}{2}\cdot (1.606\times 10^{-8}\,C)\cdot (400\,V)

U = 3.212\times 10^{-6}\,J

U = 3.212\,\mu J

3 0
3 years ago
Read 2 more answers
A 50 kg rock climber accidentally falls from the side of a rock and freefalls until she is stopped by her 9 m saftey rope. Assum
olchik [2.2K]

Answer:

a) 665 kg.m/s

b) 2.97 kN

Explanation:

The impulse is given by:

J=\Delta p\\J=m(v_a-v_b)

where

va=velocity after

vb=velocity before

The velocity just before is given by:

v_b=\sqrt{2*9.81m/s^2*9m}=13.3m/s(-\hat{j})

The velocity just after is zero because there wasn't a rebound.

So the impulse is:

J=50kg*(0-13.3m/s(-\hat{j}))\\J=50kg*(0+13.3m/s(\hat{j}))=665kg.m/s

The impulse is also given by:

J=\Delta p=F* \Delta t\\so:\\F=\frac{J}{\Delta t}\\\\F=\frac{665kg.m/s}{0.224s}=2.97kN

8 0
3 years ago
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