Answer:
-1786.5J
Explanation:
Temperature 1=T1=25°c
Temperature 2=T2=200°c
Pressure P1=1bar
Pressure P2=0.5bars
T=37°c+273=310k
Note number if moles=1
Recall work done =2.3026RTlogp2/P1
2.3026*8.314*310log(0.5/1)
-1786.5J
Answer:
the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s
Explanation:
Pitot tube

U = velocity(m/s)
= stagnation pressure (pa)
= static pressure (pa)
d = fluid density(kg/m³)

v = true velocity
= 101325 + 1/2(1.225)(25)²


d = 1.225kg/m³

the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s
Answer:
change in y = -7
change in x = -17
magnitude of displacement = sqrt(7^2+17^2)
tan of angle below -x axis = 7/17
because in third quadrant where x and y are negative