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Taya2010 [7]
3 years ago
8

A resistor rated at 250 k Ω is connected across two D cell batteries (each 1.50 V) in series, with a total voltage of 3.00 V. Th

e manufacturer advertises that their resistors are within 5% of the rated value. What are the possible minimum current and maximum current through the resistor?
Physics
1 answer:
Andrej [43]3 years ago
6 0

Given Information:  

Resistance = R = 250 Ω

Voltage = V = 3 V

Tolerance =   ±5%

Required Information:  

Maximum current = Imax = ?

Minimum current = Imin = ?

Answer:  

Imax = 12.6 uA

Imin = 11.4 uA

Explanation:  

As we know from Ohm's law

I = V/R

The current will be maximum when R is minimum and the current will be minimum when R is maximum

Rmax = 250,000 + 0.05*250,000

Rmax = 250,000 + 12500

Rmax = 262500 Ω

Rmin = 250,000 - 0.05*250,000

Rmin = 250,000 - 12500

Rmin = 237500 Ω

Imax = V/Rmin

Imax = 3/237500

Imax = 12.6 uA

Imin = V/Rmax

Imin = 3/262500

Imin = 11.4 uA

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Put all the values,

I=\dfrac{1.3\times 2.1}{4\pi \times 10^{-7}\times 1000}\\\\I=2172.46\ A

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A 3.50-meter length of wire with a cross-sectional area of 3.14 × 10-6 meter2 is at 20° Celsius. If the wire has a resistance of
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Explanation:

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Answer:

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