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jarptica [38.1K]
3 years ago
6

Indicate the changes (increases, decreases, does not change) in its volume when the pressure undergoes the following changes at

constant temperature and amount of gas. Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer. ResetHelp 1. The pressure increases to 6.0 atm. The volume The pressure increases to 6.0 a t m. The volume blank.. 2. The pressure drops to 0.40 atm. The volume The pressure drops to 0.40 a t m. The volume blank.. 3. The pressure remains at 2.0 atm. The volume The pressure remains at 2.0 a t m. The volume blank..
Chemistry
1 answer:
Inga [223]3 years ago
8 0

The question is missing information. Here is the complete question.

A gas at a pressure of 2.0 atm is in a closed container. Indicate the changes (if any) in its volume when the pressure undergoes the following changes at constant temperature and constant amount of gas. Match the words in the left with the column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer.

1. The pressure increases to 6.0 atm. The volume ________

2. The pressure drops to 0.40 atm. The volume _________

3. The pressure remains at 2.0 atm. The volume _________

Answer: 1. Decreases

2. Increases

3. Does not change

Explanation: According to the Ideal Gas Law, <u>Pressure</u>, <u>Volume</u> and <u>Temperature</u> of an ideal gas is related, as the following: PV = nRT.

In this case, since temperature (T) and amount of gas (n) are constant, the <em><u>Boyle's</u></em> <em><u>Law</u></em> can be used.

The law states that the volume of a given gas, under the conditios of temperature and amount of it are constant, is inversely proportional to the applied pressure: P₁.V₁ = P₂.V₂

  • For case 1.)

Initial P (P₁) = 2

Initial V (V₁) = V

Final P (P₂) = 6

P₁.V₁ = P₂.V₂

2.V = 6.V₂

V₂ = 1/3V

When the pressure increases to 6 atm, volume <em><u>decreases</u></em> by 1/3.

  • For case 2.)

P₁ = 2

V₁ = V

P₂ = 0.4

2.V = 0.4V₂

V₂ = 5V

When pressure drops to 0.4 atm, volume <em><u>increases</u></em> by 5.

  • For case 3.)

Since there are no change in the pressure, the volume is the same from the beginning, so <em><u>does not change</u></em>.

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Explanation:

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by cross multiplication , we get

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What is the mass of a sample of alcohol (specific heat = 2.4 J/gC), if it requires 4780 J of heat to raise the temperature by 5.
insens350 [35]

The mass of a sample of alcohol is found to be = m = 367 g

Hence, it is found out that by raising the temperature of the given product, the mass of alcohol would be 367 g.

Explanation:

The Energy of the sample given is q = 4780

We are required to find the mass of alcohol m = ?

Given that,

The specific heat given is represented by = c = 2.4 J/gC

The temperature given is ΔT = 5.43° C

The mass of sample of alcohol can be found as follows,

The formula is c = \frac{q}{mt}

We can drive value of m bu shifting m on the left hand side,

m = \frac{q}{ct}

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m = 367 g

Therefore, The mass of the given sample of alcohol is

m = 367g

It requires 4780 J of heat to raise the temperature by 5.43 C in the process which yields a mass of 367 g of alcohol.

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