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Dovator [93]
3 years ago
11

Which statement is true for a solution when its concentration of hydroxide ions increases? It becomes more acidic. It becomes le

ss alkaline. Its pH value increases. Its pH value decreases.
Chemistry
2 answers:
alexira [117]3 years ago
6 0

Answer: Option (c) is the correct answer.

Explanation:

When we increase the concentration of a substance then it means we are increasing number of molecules of the substance. So, when there is increase in concentration of hydroxide ions the it means there are more number of OH^{-} ions into the solution.

Also, it is known that pOH = log \frac{1}{OH^{-}}

Since there is increase in [OH^{-}] concentration so, this means that there will be decrease in the value of pOH.

Also,   pH + pOH = 14

so,                pH = 14 - pOH

                    pH = +ve

Thus, we can conclude that there will be increase in the value of pH.

makvit [3.9K]3 years ago
5 0

Answer:

Its pH value increases.

Explanation:

pH is the measure of alkalinity or acidity of a compound.

pH = - log [H+]

and pH + pOH = 14

where pOH is the measure of basicity of a solution, given by -log[OH-]

As a solution gets more basic that is higher [OH-], the pH increases, and on the other hand, as the pH of a solution decreases by one pH unit, the concentration of H+ increases by ten times.

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Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate
uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: m_{(AcO)_2Cu} = 0.972 g

Volume of the sodium chromate solution: V_{Na_2CrO_4} = 150.0 mL

Molarity of the sodium chromate solution: c_{Na_2CrO_4} = 0.0400 M

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

n_{(AcO)_2Cu} = 0.0053515 mol

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M

8 0
3 years ago
Please Help! I will give a Brainliest and 18 points! Please do not give me a random, gibberish answer or I will report you and g
3241004551 [841]

Answer:

V2 = 600ml

Explanation:

dilution principle formula

M1V1 = M2V2

C1V1 = C2V2

3 X 20 = 0.1 x V2

60 = 0.1 x V2

V2 = 60/0.1

V2 = 600ml

pls give brainliest

5 0
3 years ago
Read 2 more answers
Why is the water cycle called a cycle and not a system?
alexira [117]
It is called a cycle because it is repetitive, therefore making it a cycle (or almost never ending)
5 0
3 years ago
Standard notation for 31,254,000
bearhunter [10]
That seems to be standard notation
4 0
3 years ago
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zavuch27 [327]

Answer:

what would u like me to do on this?

Explanation:

do you have a tablel of elements? if not then look at on online and search them all.

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2 years ago
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