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Dovator [93]
3 years ago
11

Which statement is true for a solution when its concentration of hydroxide ions increases? It becomes more acidic. It becomes le

ss alkaline. Its pH value increases. Its pH value decreases.
Chemistry
2 answers:
alexira [117]3 years ago
6 0

Answer: Option (c) is the correct answer.

Explanation:

When we increase the concentration of a substance then it means we are increasing number of molecules of the substance. So, when there is increase in concentration of hydroxide ions the it means there are more number of OH^{-} ions into the solution.

Also, it is known that pOH = log \frac{1}{OH^{-}}

Since there is increase in [OH^{-}] concentration so, this means that there will be decrease in the value of pOH.

Also,   pH + pOH = 14

so,                pH = 14 - pOH

                    pH = +ve

Thus, we can conclude that there will be increase in the value of pH.

makvit [3.9K]3 years ago
5 0

Answer:

Its pH value increases.

Explanation:

pH is the measure of alkalinity or acidity of a compound.

pH = - log [H+]

and pH + pOH = 14

where pOH is the measure of basicity of a solution, given by -log[OH-]

As a solution gets more basic that is higher [OH-], the pH increases, and on the other hand, as the pH of a solution decreases by one pH unit, the concentration of H+ increases by ten times.

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For the reaction of C 2H 4( g) with O 2( g), to form CO 2( g) and H 2O( g), what number of grams of CO 2 could be produced from
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Answer:

4.58g of CO₂ could be produced

Explanation:

Based on the reaction:

C₂H₄(g) + 3O₂(g) → 2CO₂(g) + 2H₂O(g)

<em>1 mole of C₂H₄ reacts with 3 moles of oxygen to produce 2 moles of CO₂</em>

<em />

To solve this question we must find the moles of each reactant in order to find limiting reactant. With limiting reactant we can find the moles -And the mass- of CO₂ produced:

<em>Moles C₂H₄ -Molar mass: 28.05g/mol-</em>

2.0g * (1mol / 28.05g) = 0.0713moles

<em>Moles O₂ -Molar mass: 32g/mol-</em>

5.0g * (1mol / 32g) = 0.156moles

For a complete reaction of 0.0713 moles of C2H4 are required:

0.0713 moles C₂H₄ * (3 moles O₂ / 1 mol C₂H₄) = 0.214 moles of O₂

As there are just 0.156 moles, O₂ is limiting reactant.

The moles of CO₂ produced are:

0.156 moles O₂ * (2mol CO₂ / 3mol O₂) = 0.104 moles CO₂

The mass is -Molar mass CO₂: 44.01g/mol-

0.104 moles CO₂ * (44.01g / mol) =

<h3>4.58g of CO₂ could be produced</h3>
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