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2 years ago

1,What were you doing when you felt most passionate and alive?

Physics

2 answers:

Luba_88 [7]2 years ago

4 0

Answer:

wen I was in the car toing home from school after a bad day n si si I have crazzyyy

yanalaym [24]2 years ago

3 0

Answer:-

1. I feel the most passionate and alive when I watch BTS, because they inspir me to do many things such as Loveing Myself and doning what I love in life and chase my dream. I also feel alive when playing soccer, dancing, playing piano, or singing/rapping, because these things are what I love to do and always loved to do.

2. Yes, I feel like I live everyday the same day, some little things change but the things I do every day are the same, never changes. Wake up, eat, homework, clean, eat, tv, eat, and sleep.

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Select the correct answer.

chubhunter [2.5K]

I believe it’s self-referent encoding

3 0

2 years ago

Which characteristic does an object with a constant acceleration always have?

Alexus [3.1K]

By definition, speed is the integral of acceleration with respect to time.

We have then:

$v = \int\limits^t_0 {a} \, dt$

As the acceleration is constant, then integrating we have:

$v = a*t + vo$

Where,

vo: constant of integration that corresponds to the initial velocity

We observe then that the speed varies linearly when the acceleration is constant .

Therefore, for constant acceleration, the velocity is changing.

Answer:

an object with a constant acceleration always have:

A. changing velocity

6 0

2 years ago

Read 2 more answers

Differentiate the following functions with respect to x <br>xsin x

gtnhenbr [62]

Answer:

Here is your answer

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6 0

3 years ago

Read 2 more answers

A NASA satellite has just observed an asteroid that is on a collision course with the Earth. The asteroid has an estimated mass,

Citrus2011 [14]

Answer:

v = 7934.2 m/s

Explanation:

Here the total energy of the Asteroid and the Earth system will remains conserved

So we will have

$-\frac{GMm}{r} + \frac{1}{2}mv_0^2 = -\frac{GMm}{R} + \frac{1}{2}mv^2$

now we know that

$v_0 = 660 m/s$

$M = 5.98 \times 10^{24} kg$

$m = 5 \times 10^9 kg$

$r = 4 \times 10^9 m$

$R = 6.37 \times 10^6 m$

now from above formula

$GMm(\frac{1}{R} - \frac{1}{r}) + \frac{1}{2}mv_0^2 = \frac{1}{2}mv^2$

now we have

$2GM(\frac{1}{R} - \frac{1}{r}) + v_0^2 = v^2$

now plug in all data

$2(6.67 \times 10^{-11})(5.98 \times 10^{24})(\frac{1}{6.37 \times 10^6} - \frac{1}{4 \times 10^9}) + (660)^2 = v^2$

$v = 7934.2 m/s$

5 0

3 years ago

Approximately how much air is in a column 1-cm2 in cross section that extends from sea level to the top of the atmosphere?

laila [671]

Approximately 101 N air is in a column 1-cm2 in cross-section that extends from sea level to the top of the atmosphere

The basic level for determining height and depth on Earth is the sea level. The ocean's surface tends to seek the same level since it is one continuous body of water. However, the sea level is never fully level due to winds, currents, river discharges, and changes in gravity and temperature.

At the equator, the radius of the Earth at sea level is 6378.137 km (3963.191 mi). At the poles, it is 6,356.752 km (3,949.903 km), and on average, it is 6,371.001 km (3,958.756 mi). The elevation of the shoreline—the boundary between the ocean and the land—is referred to as sea level. Land that is higher than this altitude is above sea level, and land that is lower is below sea level.

To learn more about sea level please visit -
brainly.com/question/2113249
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8 0

2 years ago