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Sunny_sXe [5.5K]
3 years ago
11

If a girl is standing in front of a smooth surface from which a sound is reflected, the girl may hear

Physics
2 answers:
katovenus [111]3 years ago
7 0
D. Two similar sets of sounds if she is also near the source of the sound
gavmur [86]3 years ago
3 0
Near the surface of reflection, reflected wave may interfere with incident wave leading to production of constructive and as well as destructive interference. This in turn, can result to resonance as well as enhancement of the sound intensity as the waves of reflection adds to incident wave. Therefore, the girl would higher intensity of reflected waves as compared to incident waves.

Therefore, statement A is correct.
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An airplane maintains a speed of 585 km/h relative to the air it is flying through as it makes a trip to a city 815 km away to t
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Answer:

a)   t = 1.47 h    b) t = 1.32 h

Explanation:

a)  In this problem the plane and the wind are in the same North-South direction, whereby the vector sum is reduced to the scalar sum (ordinary). Let's calculate the total speed

     v = v_{f}f - v_{w}

     v = 585 -32.1

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b)  We repeat the calculation, but this time the wind is going in the direction of the plane

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      v 585 + 32.1

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What is the moment of inertia of a 2.0 kg, 20-cm-diameter disk for rotation about an axis (a) through the center, and (b) throug
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Answer:

(a) I=0.01 kg.m²

(b) I=0.03 kg.m²

Explanation:

Given data

Mass of disk M=2.0 kg

Diameter of disk d=20 cm=0.20 m

To Find

(a) Moment of inertia through the center of disk

(b) Moment of inertia through the edge of disk

Solution

For (a) Moment of inertia through the center of disk

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I=\frac{1}{2}MR^{2}\\  I=\frac{1}{2}(2.0kg)(0.20m/2)^{2}\\  I=0.01 kg m^{2}

For (b) Moment of inertia through the edge of disk

We can apply parallel axis theorem for calculating moment of inertia

I=(1/2)MR^{2}+MD\\ Here\\D=R\\I=(1/2)(2.0kg)(0.20m/2)^{2}+(2.0kg)(0.20m/2)^{2}\\  I=0.03kgm^{2}

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