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emmasim [6.3K]
3 years ago
12

Which expression is equivalent to (StartFraction 4 m n Over m Superscript negative 2 Baseline n Superscript 6 Baseline EndFracti

on) Superscript negative 2? Assume m not-equals 0, n not-equals 0. StartFraction n Superscript 6 Baseline Over 16 m Superscript 8 Baseline EndFraction StartFraction n Superscript 10 Baseline Over 16 m Superscript 6 Baseline EndFraction StartFraction n Superscript 10 Baseline Over 8 m Superscript 8 Baseline EndFraction StartFraction 4 m cubed Over n Superscript 8 Baseline EndFraction
Mathematics
2 answers:
Gennadij [26K]3 years ago
5 0

Question

Which expression is equivalent to \frac{4mn}{m^{-2}n^6}. Assuming m \neq 0; n\neq 0

Answer:

\frac{4m^3}{n^5}

Step-by-step explanation:

Given

\frac{4mn}{m^{-2}n^6}

Required:

Simplify

To simplify this, we start by splitting each individual function

\frac{4mn}{m^{-2}n^6} = \frac{4m}{m^{-2}} * \frac{n}{n^6}

From laws of indices

\frac{a^x}{a^y} = a^{x-y}

SO, the above expression can also be expressed the same way

\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{1-(-2)} * n^{1-6}

\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{1+2)} * n^{1-6}

\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{3} * n^{-5}

From laws of indices,

a^{-x} = \frac{1}{a^x}

So,

\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{3} * \frac{1}{n^5}

\frac{4m}{m^{-2}} * \frac{n}{n^6} = \frac{4m^3}{n^5}

Hence, \frac{4mn}{m^{-2}n^6} is equivalent to \frac{4m^3}{n^5}

Ann [662]3 years ago
5 0

Answer:

Option D on Edg

Step-by-step explanation:

Just did the test

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finlep [7]

Answer:

Diameter of sphere = 18 cm

Step-by-step explanation:

<h2>Volume of Cylinder and Sphere:</h2><h3> Cylinder:</h3>

     Diameter = 18 cm

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                 h = 12 cm

\sf \boxed{\bf Volume \ of \ cylinder = \pi r^2h}

                                    = π * 9 * 9 * 12 cm³

<h3>Sphere:</h3>

  \sf \boxed{\text{\bf Volume of sphere = $\dfrac{4}{3} \pi r^3$}}

Solid cylinder is melted and turned into a solid sphere.

Volume of sphere = volume of cylinder

 \sf \dfrac{4}{3}\pi r^3 = \pi *9*9*12

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6 0
1 year ago
Zaheer, a boy of height 1.5m was watching the entire programme. Initially he observed the top of the flag pole at an angle of el
7nadin3 [17]

Answer:

15.2 m

Step-by-step explanation:

You need to draw a figure. Start by drawing a horizontal segment approximately 10 cm long; that is the ground. Label the left end point A and the right endpoint B. On the right endpoint, B, go up a short 1 cm vertically. That is 1.5 m, the height of Zaheer. Label that point C. Now from that point draw a horizontal line that ends up above point A. Label that point D. Now go back to point C. Draw a segment up to the left at a 30 deg angle with CD. End the segment vertically above point D. Label that point E. That is the top of the flagpole. Draw a vertical segment down from point E through point D ending at point A. Segment AE is the flagpole. Go back to point C. Move 3 cm to the left on segment CD, and draw a point there and label it F. That is where Zaheer moved to. Now connect point F to point E. That is a 45-deg elevation to point E, the top of the flagpole.

m<EFD = 45 deg

m<EFC = 135 deg

m<FEC = 15 deg

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We now use the law of sines to find EC

(sin 15)/10 = (sin 135)/EC

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Because of the 30-60-90 triangle, ED = EC/2

ED = 13.66

Now we add the height of Zaheer to find AE.

13.66 + 1.5 = 15.16

Answer: 15.2 m

7 0
3 years ago
circle terms and simplify each of the following expressions. a. 3+1 *4+(-7) b. 50=3(-10)=2(-20) c.4+(-50)*2 d. (4+(-170))(5+(-4)
zhannawk [14.2K]

A. 3+4-7

0

B. 50=-30=-40

50=/=-30=/=-20

No solution

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-96

D. (-166)(1)

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Evaluate the expression h-6 when h=15
Monica [59]
Hello there!

h - 6
When h = 15

All we have to do is replace h by 15

h - 6
15 - 6
= 9

Good luck!
7 0
3 years ago
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horsena [70]
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