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emmasim [6.3K]
3 years ago
12

Which expression is equivalent to (StartFraction 4 m n Over m Superscript negative 2 Baseline n Superscript 6 Baseline EndFracti

on) Superscript negative 2? Assume m not-equals 0, n not-equals 0. StartFraction n Superscript 6 Baseline Over 16 m Superscript 8 Baseline EndFraction StartFraction n Superscript 10 Baseline Over 16 m Superscript 6 Baseline EndFraction StartFraction n Superscript 10 Baseline Over 8 m Superscript 8 Baseline EndFraction StartFraction 4 m cubed Over n Superscript 8 Baseline EndFraction
Mathematics
2 answers:
Gennadij [26K]3 years ago
5 0

Question

Which expression is equivalent to \frac{4mn}{m^{-2}n^6}. Assuming m \neq 0; n\neq 0

Answer:

\frac{4m^3}{n^5}

Step-by-step explanation:

Given

\frac{4mn}{m^{-2}n^6}

Required:

Simplify

To simplify this, we start by splitting each individual function

\frac{4mn}{m^{-2}n^6} = \frac{4m}{m^{-2}} * \frac{n}{n^6}

From laws of indices

\frac{a^x}{a^y} = a^{x-y}

SO, the above expression can also be expressed the same way

\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{1-(-2)} * n^{1-6}

\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{1+2)} * n^{1-6}

\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{3} * n^{-5}

From laws of indices,

a^{-x} = \frac{1}{a^x}

So,

\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{3} * \frac{1}{n^5}

\frac{4m}{m^{-2}} * \frac{n}{n^6} = \frac{4m^3}{n^5}

Hence, \frac{4mn}{m^{-2}n^6} is equivalent to \frac{4m^3}{n^5}

Ann [662]3 years ago
5 0

Answer:

Option D on Edg

Step-by-step explanation:

Just did the test

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Answer:

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Step-by-step explanation:

Given that:

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As "-" sign will invert the inner signs:

= -21 - 15g

I hope it will help you!!

6 0
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7 0
4 years ago
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4 0
3 years ago
Classify the polynomial 5m^10
Naily [24]

Answer:

Monomial

Step-by-step explanation:

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3 0
3 years ago
Someone can help me for all the question ?
Dvinal [7]

Answer:

1. 5

2. 3 adult tickets; 2 child tickets

3. See below

Step-by-step explanation:

1.

2 adult tickets cost 2 × $12 = $24

Subtract $24 from $64:

$64 - $24 = $40

Divide $40 by $8:

$40 ÷ $8 = 5

Answer: 5 child tickets

2.

x = number of adult tickets

y = number of child tickets

The total number of tickets is 5, so the first equation is:

x + y = 5

The cost of x adult tickets is 12x. The cost of y child tickets is 8y. The total cost is 12x + 8y. We are told the total cost is $52. The second equation is:

12x + 8y = 52

The system of equation is:

x + y = 5

12x + 8y = 52

Let's solve it by substitution.

Solve the first equation for x.

x = 5 - y

Now we substitute x in the second equation by 5 - y.

12(5 - y) + 8y = 52

Distribute:

60 - 12y + 8y = 52

Combine like terms on the left side:

-4y + 60 = 52

Subtract 60 from both sides:

-4y = -8

Divide both sides by 4.

y = 2

Substitute y = 2 in the first original equation and solve for x.

x + y = 5

x + 2 = 5

x = 3

Answer: 3 adult tickets; 2 child tickets

3.

The customer's claim is incorrect. His sum is $71. 71 is an odd number. Since all ticket prices are even numbers, it is impossible to add only even numbers and get an odd sum. A sum of several amounts of 12 and several amounts of 8 can never equal 71.

We can also show his claim is false using a system of equations.

x + y = 7

12x + 8y = 71

Use substitution.

x = 7 - y

12(7 - y) + 8y = 71

84 - 12y + 8y = 71

84 - 4y = 71

-4y = -13

y = 3.25

This means 3.25 child tickets. The problem states that tickets can be purchased only in whole numbers, so 3.25 tickets cannot be purchased, so the customer's claim is false.

4 0
2 years ago
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