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N76 [4]
3 years ago
8

I NEED HELP FAST, BRAINLIEST! :)

Chemistry
1 answer:
castortr0y [4]3 years ago
5 0

Answer:

decrease is the answer i think

Explanation:

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What is the correct description of the components of an ATP molecule?
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It's adenosine triphosphate !

it has Penrose sugar and phosphate as backbone !
and nitrogenous base ... adenine.... in the middle !
4 0
3 years ago
What type of reaction is shown below? Check all that apply. Ca + 2H2O → Ca(OH)2 + H2 synthesis decomposition combustion single r
Ksju [112]

The balanced reaction is

Ca + 2H2O → Ca(OH)2 + H2

Here this reaction can be compared with

A + BC  ---> AB + C

So here one reactant (A) is accepting a group which is being given by another compound (BC) however the A is not giving any group / element or ion

So this single displacement

Similarly in the given reaction

the anion OH- is only being replaced

The element Ca accepts OH- and H2O loses the same group to form new element H2

So the correct answer is

Single replacement also known as single displacement


3 0
2 years ago
Read 2 more answers
Moraines left by glaciers are different from deposits left by rivers because the rocks left behind are _____.
12345 [234]

Explanation:

unorganized and unsorted i think this is the answer

7 0
3 years ago
Explain specifically how an electron gives off light in an atom.
exis [7]

Answer:

Then, at some point, these higher energy electrons give up their "extra" energy in the form of a photon of light, and fall back down to their original energy level.

Explanation:

When properly stimulated, electrons in these materials move from a lower level of energy up to a higher level of energy and occupy a different orbital.

3 0
2 years ago
Using the reaction below: 2 CO2(g) + 2 H2O(l) → C2H4(g) + 3 O2(g) ΔHrxn= +1411.1 kJ What would be the heat of reaction for this
maw [93]

Answer:  d) -705.55 kJ

Explanation:

Heat of reaction is the change of enthalpy during a chemical reaction with all substances in their standard states.

2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g) \Delta H=+1411.1kJ

Reversing the reaction, changes the sign of \Delta H

C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)

\Delta H=-1411.1kJ

On multiplying the reaction by \frac{1}{2} , enthalpy gets half:

0.5C_2H_4(g)+1.5O_2(g)\rightarrow CO_2(g)+H_2O(l)\Delta H=\frac{1}{2}\times -1411.1kJ=-705.55kJ/mol

Thus the enthalpy change for the given reaction is -705.55kJ

7 0
3 years ago
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