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anyanavicka [17]
3 years ago
12

Hc1 is the formula for .

Chemistry
1 answer:
PIT_PIT [208]3 years ago
5 0

Answer:

HCl is the formula for Hydrochloric acid

Explanation:

  • Chemical formula is a formula of a compound showing the symbols of elements present in the compound.
  • Chemical formula also shows the number of atoms of each element present in a compound.
  • HCl is the chemical formula of hydrochloric acid. From this formula we can tell that hydrochloric acid is made up of hydrogen and chlorine elements.
  • The formula also shows that HCl contains 1 hydrogen atom and 1 chlorine atom.
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Answer:

A, Makes the leg move

Explanation:

6 0
3 years ago
Please begging you guys someone help me
BaLLatris [955]

Answer:

See Explanation

Explanation:

10) From the options provided for this question, gamma particle is the most energetic. Recall that gamma rays are high energy electromagnetic radiation which are capable of causing a high degree of ionization in matter.

11) The bombardment of U-235 with neutrons leads to the reaction;

U\frac{235}{92}  + n\frac{1}{0}---> I\frac{138}{53}  + Y\frac{95}{39} +3n \frac{1}{0}

Hence

a = 92, b= 95, c= 53

12) In positron emission, a proton is transformed into a neutron. The mass number of the daughter nucleus is the same as its parent but the atomic number decreases by 1.

Hence;

Th\frac{231}{90} -----> e\frac{1}{0} +Ac \frac{231}{89}

4 0
3 years ago
A student dissolves 3.9g of aniline (C6H5NH2) in 200.mL of a solvent with a density of 1.05 g/mL . The student notices that the
Tresset [83]

Answer:

a. Molarity= M =2.1x10^{-1}M

b. Molality= m=2.0x10^{-1}m

Explanation:

Hello,

In this case, given the information about the aniline, whose molar mass is 93g/mol, one could assume the volume of the solution is just 200 mL (0.200 L) as no volume change is observed when mixing, therefore, the molarity results:

M=\frac{n_{solute}}{V_{solution}} =\frac{3.9g*\frac{1mol}{93g} }{0.2L} =2.1x10^{-1}M

Moreover, the molality:

m=\frac{n_{solute}}{m_{solvent}} =\frac{3.9g*\frac{1mol}{93g} }{0.2L*\frac{1.05kg}{1L} } =2.0x10^{-1}m

Best regards.

7 0
3 years ago
How many moles of ammonia gas occupy 50 mL at at 700 kPa and 30.0 0C?
nalin [4]

For the conversions

I will start with pressure
1atm=101.3kPa
x =700kPa
x=700kPa/101.3kPa
x=6.91atm

Temperature
273K+30.00C
303K

Volume
1L=1000ml
x =50ml
x=0.05L

PV=nRT
6.91*0.05=n*0.08206*303
0.3455=24.86418n
0.3455/24.86418=n
0.0138=n
number of moles = 0.0138moles

Note: 0.08206 is the gas constant in this case
6 0
3 years ago
What's the equation for the reaction of Trifluoro bromide with Ammonia gas. ( brainliest assured )​
sp2606 [1]

Answer:

Ammonium bromide can be prepared by the direct action of hydrogen bromide on ammonia. It can also be prepared by the reaction of ammonia with iron(II) bromide or iron(III) bromide, which may be obtained by passing aqueous bromine solution over iron filings.

Explanation:

please mark me as brainliest thank you

5 0
3 years ago
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