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Blizzard [7]
3 years ago
14

Do charges exit a circuit with less energy than they had when they entered the circuit

Physics
1 answer:
forsale [732]3 years ago
8 0
False energy can never be lost
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What is light emitting diode<br>​
Natali [406]

Answer:

A light emitting diode (a semiconductor diode which glows when voltage is applied.

8 0
3 years ago
wo skaters collide and embrace in an inelastic collision. Alex's mass is 90 kg and his initial velocity is 1.5 m/s i . Barbara's
Natalija [7]

Answer:

The two skaters will move with a common speed of 1.19 m/s.

Explanation:

Given that,

Mass of Alex, m_1=90\ kg

Initial velocity of Alex, u_1=1.5i\ m/s

Mass of Barbara, m_2=57\ kg

Initial velocity of Barbara, u_2=2j\ m/s

After the collision, the two skaters move together at a common velocity. Let V is the common velocity. Using the conservation of momentum as :

m_1u_1+m_2u_2=(m_1+m_2)V\\\\90\times 1.5i+57\times 2j=(90+57)V\\\\V=\dfrac{135i+114j}{147}\\\\V=\dfrac{135i}{147}+\dfrac{114j}{147}\\\\V=(0.91i+0.77j)\ m/s

Magnitude of final velocity:

|V|=\sqrt{0.91^2+0.77^2} \\\\|V|=1.19\ m/s

So, the two skaters will move with a common speed of 1.19 m/s.

3 0
4 years ago
Read 2 more answers
Ted wants to hang a wall clock on the wall by using a string. If the mass of the wall clock is 0.250 kilograms, what should be t
Ahat [919]
The clock is pulling the force towards earth's center because of gravity.
That force is equal to:
F = m*g   where g is gravitational acceleration. 

We will take that g = 9.81m/s^2

Now:
F = 0.25 * 9.81 = 2.4525 N

The string needs to sustain that force, therefore minimum Force that string has to be able to sustain is:
2.4525 N
8 0
3 years ago
Read 2 more answers
Three people are pushing a 500 kg of box in the same direction. applied forces are 30 n, 20 n, and 10 n respectively. if the acc
GREYUIT [131]
The total force applied by the three people is:
F=30 N+20 N+10 N=60 N
This force is pushing toward the direction of the motion, while the  frictional force F_f points in the opposite direction.
We can write Newton's second law applied to the block: the resultant of the two forces must be equal to the product between the block's mass and its acceleration
F-F_f = ma
We know the mass of the block, m=500 kg, and the acceleration, a=0.02 m/s^2, so we can find the friction:
F_f = F-ma=60 N - (500 kg)(0.02 m/s^2)=50 N
8 0
4 years ago
The fire alarm goes off, and a 75 kg firefighter slides down a pole with a constant acceleration of a = 6 m/s square. What is th
Alex17521 [72]

Answer:

450N

Explanation:

Given data

Mass m= 75kg

Acceleration= 6m/s^2

From the Newtons first law, F=ma

substitute

F=75*6

F= 450N

Hence the force is 450N

3 0
3 years ago
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