All categories

4 years ago

What would happen if the earth’s mantle was completely solid? Why do you think so?

Physics

1 answer:

Keith_Richards [23]4 years ago

4 0

Answer:

The earth's mantle is comprised of silicate rocks that are usually in the form of liquid. Its thickness is nearly 2,900 kilometres, forming about 85% of the total volume of the Earth. One of the main significance of this layer is the formation of the convection current, that initiates due to the heat energy provided from the interior of the earth, as a result of which the lithospheric plates above the layer of asthenosphere move from one place to another with respect to a fixed pole.

But, if the earth's mantle was entirely solid in nature then these heat energy from the core of the earth would not be sufficient to form these convection currents, due to which the plates would have not moved and there would have existed only a large super-continent and a huge water body.

You might be interested in

A. What is the RMS speed of Helium atoms when the temperature of the Helium gas is 343.0 K? (Possibly useful constants: the atom

kkurt [141]

Answer:

(a) 1462.38 m/s

(b) 2068.13 m/s

Explanation:

(a)

The Kinetic energy of the atom can be given as:

K.E = (3/2)KT

where,

K = Boltzman's Constant = 1.38 x 10⁻²³ J/k

K.E = Kinetic Energy of atoms = 343 K

T = absolute temperature of atoms

The K.E is also given as:

K.E = (1/2)mv²

Comparing both equations:

(1/2)mv² = (3/2)KT

v² = 3KT/m

v = √[3KT/m]

where,

m = mass of Helium = (4 A.M.U)(1.66 X 10⁻²⁷ kg/ A.M.U) = 6.64 x 10⁻²⁷ kg

v = RMS Speed of Helium Atoms = ?

Therefore,

v = √[(3)(1.38 x 10⁻²³ J/K)(343 K)/(6.64 x 10⁻²⁷ kg)]

v = 1462.38 m/s

(b)

For double temperature:

T = 2 x 343 K = 686 K

all other data remains same:

v = √[(3)(1.38 x 10⁻²³ J/K)(686 K)/(6.64 x 10⁻²⁷ kg)]

v = 2068.13 m/s

8 0

3 years ago

A 328-kg car moving at 19.1 m/s in the + x direction hits from behind a second car moving at 13.0 m/s in the same direction. If

Kisachek [45]

Answer:

+14.0 m/s

Explanation:

we have mV + Mv = mU + Mu we solve for U = (mV + Mv - Mu)/m = (328*19.1 + 790*13 - 790*15.1)/328 = 14. Answer

8 0

3 years ago

A 12.0-m wire with a mass of 145 g is under tension. A transverse wave, for which the frequency is 630 Hz, the wavelength is 0.5

miskamm [114]

Answer:

The maximum traverse acceleration is $\alpha = 31346.095 m/s^2$

Explanation:

Generally the maximum transverse acceleration is mathematically represented as

$\alpha = w^2 A$

Where $w$ is the angular velocity which is mathematically evaluated as

$w = 2 \pi f$

Substituting the values given in the question

$w = 2 * 3.142 * 630$

$= 3958.92 rad/s$

A is the A is amplitude with a value of 2.0mm $= \frac{2}{1000} = 0.002m$

Substituting this into the formula for maximum transverse acceleration

$\alpha = 3958.96^2 * 0.002$

$= 31346.095 m/s^2$

4 0

4 years ago

How does the air in a bicycle tyre cause pressure?

FromTheMoon [43]

The air inside the Tyre causes pressure because the particles bump into each other and cause pressure the more they bump into each other or their container the higher the pressure is.

3 0

4 years ago

The nose of an ultralight plane is pointed south, and its airspeed indicator shows 28 m/s . the plane is in a 18 m/s wind blowin

leva [86]

Here I think you have to find the velocity in x and y components where x is east and y is north
So as air speed indicator shows the negative speed in y component and adding it in
air speed while multiplying with the direction component we will get the velocity as velocity is a vector quantity so direction is also required
v=-28 m/s y + 18 m/s (- x/sqrt(2) - y/sqrt(2))
solving
v= -12.7 m/s x-40.7 m/s y
if magnitude of velocity or speed is required then
speed= sqrt(12.7^2 + 40.7^2)
speed= 42.63 m/s
if angle is asked
angle = arctan (40.7/12.7)
angle = 72.67 degrees south of west

6 0

4 years ago