Answer:
d) V = 91.3 L
Explanation:
Given data:
Volume of nitrogen = ?
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Number of atoms of nitrogen = 2.454×10²⁴ atoms
Solution:
First of all we will calculate the number of moles of nitrogen by using Avogadro number.
1 mole = 6.022×10²³ atoms
2.454×10²⁴ atoms × 1 mol / 6.022×10²³ atoms
0.407×10¹ mol
4.07 mol
Volume of nitrogen:
PV = nRT
1 atm × V = 4.07 mol ×0.0821 atm.L /mol.K ×273.15 K
V = 91.3 atm.L /1 atm
V = 91.3 L
Answer:
B
Explanation:
To calculate questions like this, you need to make use of the equation below:
ν = c / λ
ν is the frequency, c is the speed of light, and λ is the wavelength
ν = c / λ
2.45 • 10^9 Hz = (3•10^8 m/s)/(λ)
λ = 0.122 m = B
Answer:
The formulas that will be used are:
Situation one:
The moon will be experiencing gravitational force in the form of centripetal force, so we equate the two formulas.
Gravitational force = GMm /r²
Centripetal force = mv²/r
Equating,
GMm/r² = mv²/r
v² = GM/r
The first scenario will use the formula v² = GM/r
Situation 2:
The second situation will use the simple distance over time formula for velocity, where the distance will be the circumference and the time will be in seconds.
v = 2rπ/t
Explanation: