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____ [38]
3 years ago
14

In a sample of oxygen gas at room temperature, the average kinetic energy of all the balls stays constant. Which postulate of ki

netic molecular theory best explains how this is possible?
A. Attractive forces between gas particles are negligible because the particles of an ideal gas are moving so quickly.
B. Collisions between gas particles are elastic; there is no net gain or loss of kinetic energy.
C. Gases consist of a large number of small particles, with a lot of space between the particles.
D. Gas particles are in constant, random motion, and higher kinetic energy means faster movement.
Chemistry
1 answer:
Levart [38]3 years ago
7 0

Answer:

Collisions between gas particles are elastic; there is no net gain or loss of kinetic energy.

Explanation:

When a gas is paced in a container, the molecules of the gas have little or no intermolecular interaction between them. There is a lot of space between the molecules of the gas.

The gas molecules move at very high speed and collide with each other and with the walls of container.

The collision of these particles with each other is perfectly elastic hence the kinetic energy of the colliding gas particles do not change.

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3 0
3 years ago
If 0.750 L of argon at 1.50 atm and 177°C and 0.235 L of sulfur dioxide at 95.0 kPa and 63.0°C are added to a 1.00-L flask and t
Furkat [3]

Answer:

The resulting pressure in the flask is 0.93 atm

Explanation:

- Apply the Ideal Gas law in both cases to get the mols, of Ar and SO2.

- Once you know the mols, sum both to get the total mols in the mixture.

- Apply the Ideal Gas lawin the flask with the total mols to know the resulting pressure.

First: 0.750 L of argon at 1.50 atm and 177°C

T° C + 273 = T° K → 177°C + 273 = 450K

P .V = n . R . T

1.50 atm . 0.750 L = n . 0.082 L.atm/mol.K  . 450K

(1.50 atm . 0.750 L) /  (0.082 mol.K/L.atm  . 450K) = n

0.030 mols Ar = n

Be careful with the R units, the ideal gases constant

Let's convert kPa to atm.

101.33 kPa _____ 1 atm

95 kPa ________ (95 / 101.33) = 0.94 atm

T° C + 273 = T° K → 63°C + 273 = 336 K

0.94 atm . 0.235 L = n . 0.082 L.atm/mol.K . 336K

(0.94 atm . 0.235 L) / (0.082 mol.K/L.atm . 336K) = n

8.01X10⁻³ mols = n

0.030 mols Ar  + 8.01X10⁻³ mols SO₂ = 0.038 total mols in the mixture

1L . P = 0.038 mol . 0.082 L.atm / mol.K . 298 K

P = (0.038 mol . 0.082 L.atm / mol.K . 298 K ) / 1L

P = 0.93 atm

7 0
3 years ago
What is the basic unit of mass in the metric system?
Ilya [14]
The basic unit of mass in the metric system is grams
7 0
3 years ago
Read 2 more answers
8. Rewrite each of the following as an "ordinary” decimal
saveliy_v [14]

Answer:

????????

Explanation:

3 0
3 years ago
What is the name of this compound? H single bonded to N with a pair of electron dots above and a single bond to H below, single
dybincka [34]

Answer:

Ethanamine (also known as ethylamine)

Explanation:

The compound that is requested by the question is ethanamine. Its trivial name is ethylamine.

It is a compound that contained the ethyl moiety (CH3CH2-) as well as the amine moiety (-NH2).

Ethanamine has a structure that can easily be determined by the statements in the question.

The structure of ethanamine is shown in the image attached.

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3 years ago
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