Answer:
<u>Answer (a):</u>
s + l = 22 ... (i)
43s + 75l = 1234 ... (ii)
<u>Answer (b)</u>
9 large dogs.
Step-by-step explanation:
Paws at Play made a total of $1234 grooming 22 dogs.
Paws at Play charges $43 to groom each small dog and;
$75 for each large dog.
Let the number of small dogs be 's'
And the number of large dogs be 'l'
<u>A system of equations will be:</u>
s + l = 22 ... (i)
43s + 75l = 1234 ... (ii)
Solving this set of simultaneous equations by elimination, we simply multiply (i) by 43 to get;
43s + 43l = 946 ... (i)
43s + 75l = 1234 ... (ii)
Subtracting (i) from (ii) we get;
32l = 288 , l = 
= 9
So there are 9 large dogs.
Answer:
The value is 78
Step-by-step explanation:
We need to add them all together
6+15+24+33
78
Answer:
sure I'll help, 59.99 per hour. it's a pretty solid deal.
Step-by-step explanation:
Answer:
m = 68 - c
Step-by-step explanation:
It is given that Tegan needs to make 68 more snow blocks to finish building an igloo.
Let m be the number of blocks Tegan still needs to make and c be the number of completed blocks.
If total number of required block is 68 and c blocks are completed then the remaining blocks is the difference between 68 and c.
Number of blocks Tegan still needs to make = 68 - c
We know that c represent the number of blocks Tegan still needs to make.
m = 68 - c
Therefore, the required equation is m = 68 - c.
1 is B
2 is A
3 is E
4 is C
5 is D
