Answer:
101.54m/h
Explanation:
Given that the buses are 5mi apart, and that they are both driving at the same speed of 55m/h, rate of change of distance can be determined using differentiation as;
Let l be the be the distance further away at which they will meet from the current points;
#The speed toward each other.
Hence, the rate at which the distance between the buses is changing when they are 13mi apart is 101.54m/h
Answer:
<u>I had to search the Figure on Google to solve this question.</u>
a) The magnitude of the force F₃ is:
And the direction of F₃:
(with respect to the y-direction, in the third quadrant)
b) P = 4.22 N
Explanation:
<u>I had to search the Figure on Google to solve this question.</u>
a) We can find the force of the third person as follows:
So, in x-direction we have:
In y-direction we have:
The magnitude of the force F₃ is:
To find the direction of F₃ we need to calculate its angle with respect to the y-direction (in the third quadrant):
<em>b) If the third person exerts the force found in part (a) the car will stop, so the only way for the cart to accelerate at 200 m/s² is that the third person does not exert the force found in a. </em>
<u>To find the weight of the cart when it accelerates at 200 m/s², we need to consider: F₃ = 0</u>.
First, we need to find the cart's mass. Since the car is moving in the x-direction we have:
Now, the weight of the cart is:
I hope it helps you!