Answer:
0.36 A.
Explanation:
We'll begin by calculating the equivalent resistance between 35 Ω and 20 Ω resistor. This is illustrated below:
Resistor 1 (R₁) = 35 Ω
Resistor 2 (R₂) = 20 Ω
Equivalent Resistance (Rₑq) =?
Since, the two resistors are in parallel connections, their equivalence can be obtained as follow:
Rₑq = (R₁ × R₂) / (R₁ + R₂)
Rₑq = (35 × 20) / (35 + 20)
Rₑq = 700 / 55
Rₑq = 12.73 Ω
Next, we shall determine the total resistance in the circuit. This can be obtained as follow:
Equivalent resistance between 35 Ω and 20 Ω (Rₑq) = 12.73 Ω
Resistor 3 (R₃) = 15 Ω
Total resistance (R) in the circuit =?
R = Rₑq + R₃ (they are in series connection)
R = 12.73 + 15
R = 27.73 Ω
Finally, we shall determine the current. This can be obtained as follow:
Total resistance (R) = 27.73 Ω
Voltage (V) = 10 V
Current (I) =?
V = IR
10 = I × 27.73
Divide both side by 27.73
I = 10 / 27.73
I = 0.36 A
Therefore, the current is 0.36 A.
Red shift of distant galaxies
Answer:
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Answer:
Van der Waal's equation
Explanation:
The Van der Waal's equation is use to calculate the properties of a gas under nonideal or real gases conditions.
.
Here P, V ,T ,n and R have usual meaning as in the ideal gas equation
that is PV=nRT
with the difference of constant a and b. a and b are constants representing magnitude of intermolecular attraction and excluded volume respectively respectively.
Answer:
65.9°
Explanation:
When light goes through air to glass
angle of incidence, i = 35°
refractive index, n = 1.5
Let r be the angle of refraction
Use Snell's law


Sin r = 0.382
r = 22.5°
Now the ray is incident on the glass surface.
A = r + r'
Where, r' be the angle of incidence at other surface
r' = 60° - 22.5° = 37.5°
Now use Snell's law at other surface

Where, i' be the angle at which the light exit from other surface.

Sin i' = 0.913
i' = 65.9°