Answer:
Rate constant of the reaction is 
.
Explanation:
A + B + C → D + E
Let the balanced reaction be ;
aA + bB + cC → dD + eE
Expression of rate law of the reaction will be written as:
![R=k[A]^a[B]^b[C]^c](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5Ea%5BB%5D%5Eb%5BC%5D%5Ec)
Rate(R) of the reaction in trail 1 ,when :
![[A]=0.30 M,[B]=0.30 M,[C]=0.30 M](https://tex.z-dn.net/?f=%5BA%5D%3D0.30%20M%2C%5BB%5D%3D0.30%20M%2C%5BC%5D%3D0.30%20M)
![9.0\times 10^{-5} M/s=k[0.30 M]^a[0.30 M]^b[0.30 M]^c](https://tex.z-dn.net/?f=9.0%5Ctimes%2010%5E%7B-5%7D%20M%2Fs%3Dk%5B0.30%20M%5D%5Ea%5B0.30%20M%5D%5Eb%5B0.30%20M%5D%5Ec)
...[1]
Rate(R) of the reaction in trail 2 ,when :
![[A]=0.30 M,[B]=0.30 M,[C]=0.90 M](https://tex.z-dn.net/?f=%5BA%5D%3D0.30%20M%2C%5BB%5D%3D0.30%20M%2C%5BC%5D%3D0.90%20M)
![2.7\times 10^{-4} M/s=k[0.30 M]^a[0.30 M]^b[0.90 M]^c](https://tex.z-dn.net/?f=2.7%5Ctimes%2010%5E%7B-4%7D%20M%2Fs%3Dk%5B0.30%20M%5D%5Ea%5B0.30%20M%5D%5Eb%5B0.90%20M%5D%5Ec)
...[2]
Rate(R) of the reaction in trail 3 ,when :
![[A]=0.60 M,[B]=0.30 M,[C]=0.30 M](https://tex.z-dn.net/?f=%5BA%5D%3D0.60%20M%2C%5BB%5D%3D0.30%20M%2C%5BC%5D%3D0.30%20M)
![3.6\times 10^{-4} M/s=k[0.60 M]^a[0.30 M]^b[0.30 M]^c](https://tex.z-dn.net/?f=3.6%5Ctimes%2010%5E%7B-4%7D%20M%2Fs%3Dk%5B0.60%20M%5D%5Ea%5B0.30%20M%5D%5Eb%5B0.30%20M%5D%5Ec)
...[3]
Rate(R) of the reaction in trail 4 ,when :
![[A]=0.60 M,[B]=0.60 M,[C]=0.30 M](https://tex.z-dn.net/?f=%5BA%5D%3D0.60%20M%2C%5BB%5D%3D0.60%20M%2C%5BC%5D%3D0.30%20M)
![3.6\times 10^{-4} M/s=k[0.60 M]^a[0.60 M]^b[0.30 M]^c](https://tex.z-dn.net/?f=3.6%5Ctimes%2010%5E%7B-4%7D%20M%2Fs%3Dk%5B0.60%20M%5D%5Ea%5B0.60%20M%5D%5Eb%5B0.30%20M%5D%5Ec)
...[4]
By [1] ÷ [2], we get value of c ;
c = 1
By [3] ÷ [4], we get value of b ;
b = 0
By [2] ÷ [3], we get value of a ;
a = 2
Rate law of reaction is :
![R=k[A]^2[B]^0[C]^1](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5E2%5BB%5D%5E0%5BC%5D%5E1)
Rate constant of the reaction = k
![9.0\times 10^{-5} M/s=k[0.30 M]^2[0.30 M]^0[0.30 M]^1](https://tex.z-dn.net/?f=9.0%5Ctimes%2010%5E%7B-5%7D%20M%2Fs%3Dk%5B0.30%20M%5D%5E2%5B0.30%20M%5D%5E0%5B0.30%20M%5D%5E1)
![k=\frac{9.0\times 10^{-5} M/s}{[0.30 M]^2[0.30 M]^0[0.30 M]^1}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B9.0%5Ctimes%2010%5E%7B-5%7D%20M%2Fs%7D%7B%5B0.30%20M%5D%5E2%5B0.30%20M%5D%5E0%5B0.30%20M%5D%5E1%7D)
Answer:Conduction: Touching a stove and being burned. Ice cooling down your hand
Convection: Hot air rising, cooling, and falling (convection currents)
Radiation: Heat from the sun warming your face
Explanation:
Vaccine
Because scientists normally put the cure in a form to get injected into you and since a vaccine is basically a shot vaccine would most likely be correct
<span>your answer is Ca3</span>(PO4)2<span>, </span>
Answer:
Aluminium.
Explanation:
The above electronic configuration can be written in a simplified form as shown below:
1s² 2s²2p⁶ 3s²3p¹
Next, we shall determine the number of electrons in the atom of the element as follow:
Number electron = 2 + 2 + 6 + 2 + 1
Number of electron = 13
Next, we shall determine the number of protons.
Since the element is in its neutral state,
The number of electrons and protons are equal i.e
Proton = Electron
Number of electron = 13
Proton = Electron = 13
Proton = 13
Next, we shall determine the atomic number of the element.
The atomic number of an element is simply the number of protons in the atom of the element i.e
Atomic number = proton number
Proton = 13
Atomic number = 13
Comparing the atomic number of the element with those in the periodic table, the element with the above electronic configuration is aluminium since no two elements have the same atomic number.
