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Zanzabum
3 years ago
5

You have a glass of water with a volume of 250 mL and a temperature of 12 degrees Celsius. You add a piece of dry ice, CO2(s), w

hich has a mass of 25 g, to cool down his water. If dry ice has an enthalpy of sublimation of 25.2 kJ/mol, calculate the final temperature of the water after the dry ice has fully dissolved
Chemistry
1 answer:
yuradex [85]3 years ago
5 0

Answer:

3 degress?

Explanation:

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Convert 533 cm/s to units of meters per minute. Show the unit analysis by dragging the conversion factors into the unit‑factor s
lukranit [14]

Answer:

319.8 m/min

Explanation:

533 cm/s

We can convert 533 cm/s to m/min by doing the following:

First, we shall convert 533 cm/s to m/s. This can be obtained as illustrated below:

Recall:

100 cm/s = 1 m/s

Therefore,

533 cm/s = 533 cm/s /100 cm/s × 1 m/s

533 cm/s = 5.33 m/s

Finally, we shall convert 5.33 m/s to m/min. This can be obtained as follow:

1 m/s = 60 m/min

Therefore,

5.33 m/s = 5.33 m/s / 1 m/s × 60 m/min

5.33 m/s = 319.8 m/min

Therefore, 533 cm/s is equivalent to 319.8 m/min

8 0
3 years ago
A 25.0g piece of aluminum sits in a room and cools. It loses 4300.0 J of heat. If the initial temperature of aluminum is 125.3°C
Vesna [10]

Answer:

-65.8C

Explanation:

8 0
3 years ago
How many uL are present in 250 mL of H20? (1 uL = 10^-6 Liters)​
Vanyuwa [196]

Answer:

250000 μL

Explanation:

If         1 L = 1000 mL

Then  X L = 250 mL

X = (1 × 250) / 1000 = 0.25 L

Now we can calculate the number of microliters (μL) in 0.25 L:

if        1 μL = 10⁻⁶ L

then   X μL = 0.25 L

X = (1 × 0.25) / 10⁻⁶  =250000 μL

4 0
3 years ago
A sample of gas has a mass of 0.560 g . Its volume is 125 mL at a temperature of 85 ∘C and a pressure of 757 mmHg .
-BARSIC- [3]

Answer:

132g/mole

Explanation:

using the formula PV=nRT should be used to solve for the number of moles (n).  R is a constant which is 62.3637 L mmHG/mole K.

Inorder for your units to match you will have to convert 125ml to .125L and the temperature of 85C to K . you do that by adding 273 to the 85C and get 358K.  Once you solve for n then you use that number and divide by the number of grams from the question (.560g) since molar mass is grams/moles.

4 0
3 years ago
If I have 17 liters of gas at 67C and 88.89 atm, what will be the pressure of the gas if I raise the temperature to 94C and decr
dmitriy555 [2]

Answer:

The correct answer is A. 140 atm

Explanation:

We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T. We convert the unit Celsius into Kelvin:

0 ° C = 273K, 67 ° C = 273 + 67 = 340K; 94 ° C = 273 + 94 = 367K

P1xV1 /T1= P2x V2/T2

P2= ((P1xV1 /T1)xT2)/V2

P2=((88,89atm x 17L/340K)x367K)/12L= <em>135,927625 atm</em>

7 0
3 years ago
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