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3 years ago

What is the charge of oxygen in Na2O?

Chemistry

2 answers:

Veseljchak [2.6K]3 years ago

6 0

Answer:

-2

Explanation:

- Look up oxidation rules. Most always, oxygen is a -2.

- If you want more info, Na would be +1 because 1 + 1 = 2, which balances out the -2 on Oxygen.

- Hope this helps! If you need more help or a further explanation please let me know.

Nuetrik [128]3 years ago

3 0

In Na2O, what is the oxidation state of oxygen? In Na2O oxidation state of Na is 1+

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The answer for the following problem is mentioned below.

Therefore volume occupied by methane gas is 184.78 × 10^-3 liters

Explanation:

Given:

mass of methane( $CH_{4}$ ) = 272 grams

pressure (P) = 250 k Pa =250×10^3 Pa

temperature(t) = 54°C =54 + 273 = 327 K

Also given:

R = 8.31JK-1 mol-1 ,

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We know;

According to the ideal gas equation,

P × V = n × R × T

here,

n = m÷M

n =272 ÷ 16

n = 17 moles

Therefore,

250×10^3 × V = 17 × 8.31 × 327

V = ( 17 × 8.31 × 327 ) ÷ ( 250×10^3 )

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