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vivado [14]
3 years ago
14

The addition of electron shells results in _____

Physics
1 answer:
vodka [1.7K]3 years ago
6 0

Answer:

shielding of electrons

Explanation:

The addition of electrons shells results in the shielding of electrons away from the nucleus, most importantly the nuclear pull resulting from the charge.

  • The nucleus pulls electrons to itself due to the net positive charge on it.
  • As more electronic shell is added, the effect of the pull weakens outward.
  • The inner shell experiences the nuclear pull more than the outer shell electrons.

The effect is responsible for a wide range of properties of elements.

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A person throws a pumpkin at a horizontal speed of 4.0 — off a cliff. The pumpkin travels 9.5 m horizontally
emmainna [20.7K]

Complete Question

A person throws a pumpkin at a horizontal speed of   4.0 m/s off a cliff. The pumpkin travels 9.5m horizontally before it hits the ground. We can ignore air resistance.What is the pumpkin's vertical displacement during the throw? What is the pumpkin's vertical velocity when it hits the ground?

Answer:

The  pumpkin's vertical displacement  is  H = 27 .67 \ m

The  pumpkin's vertical velocity when it hits the ground is  v_v__{f}} = 23.298 \  m/s

Explanation:

From the question we are told that

   The  horizontal speed is  v_h  =  4 m/s

    The horizontal distance traveled is  d =  9.5 \ m

The horizontal distance traveled is mathematically represented as

           S =  v_h * t

Where t is the time taken

substituting values

          9.5 =  4 * t

   =>     t =  \frac{9.5}{4}

            t = 2.38 \ sec

Now the vertical displacement is mathematically represented as

        H  =  v_v t  +  \frac{1}{2} a_v t^2

now the vertical velocity before the throw is  zero

    So

          H =  0 +  \frac{1}{2} (9.8) * (2.375)^2

          H = 27 .67 \ m

Now the final vertical velocity  is mathematically represented as

          v_v__{f}} =  v_v + at

  substituting values

             v_v__{f}} =  0 + (9.8)* (2.375)

            v_v__{f}} = 23.298 \  m/s

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3 years ago
What is the angular position in radians of the minute hand of a clock at 2:55?
OleMash [197]
Refer to the diagram shown.

There are twelve 5-minute divisions.
Each 5-minute division is equal to 360°/12 = 30°.

By convention, angles are measured counterclockwise from the positive x-axis.
The angular position of the minute hand at 2:55 is
θ = 90° + 30° = 120°

Because 360° = 2π radians, therefore
θ = (120/360)*2π = (2π)/3 radians  = 2.0944 radians

Answer: (2π)/3 radians ofr 2.0944 radians.

8 0
3 years ago
Read 2 more answers
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