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telo118 [61]
3 years ago
8

8 DO

Chemistry
1 answer:
Goryan [66]3 years ago
3 0

Answer:

Increased use of resources

Additional waste produced

More construction

Cutting down trees

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he heat of fusion of tetrahydrofuran is . Calculate the change in entropy when of tetrahydrofuran melts at . Be sure your answer
lana [24]

Answer:

\Delta S=1.8x10^{-3}\frac{kJ}{K}=1.8\frac{J}{K}

Explanation:

Hello.

In this case, given the heat of fusion of THF to be 8.5 kJ/mol and freezing at -108.5 °C, for the required mass of 5.9 g, we can compute the entropy as:

\Delta S=\frac{n*\Delta H}{T}

Whereas n accounts for the moles which are computed below:

n=5.9g*\frac{1mol}{72g} =0.082mol

Thus, the entropy turns out:

\Delta S=\frac{0.0819mol*8.5 kJ/mol}{(-108.5+273.15)K}\\\\\Delta S=1.8x10^{-3}\frac{kJ}{K}=1.8\frac{J}{K}

Best regards.

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3 years ago
Four different insect mouthparts are shown.
TiliK225 [7]

Answer:

W

Explanation:

7 0
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PLEASE HELP this is chemistry 12 points
Inessa05 [86]

Answer:

6.791

Explanation:

For proper significant figures with addition, you would use the significant figures of the number with lowest decimal place.  6.298 goes to the 10⁻³ place.  0.492712 goes to the 10⁻⁶ place.  You will go out to the 10⁻³ place.

6.298 + 0.492712 = 6.790712 ≈ 6.791

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Which process releases heat?
borishaifa [10]

Answer:

C

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burning gasoline i think pls can i have brainliest if right!

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How can I calculate the valence electrons of ions?
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First of all, you should know the valence electron of atom.

Then add charge, In case of -ve ion & subtract, in case of +ve ion.

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