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IRINA_888 [86]
3 years ago
6

What do dipole-dipole forces do?

Chemistry
2 answers:
lisabon 2012 [21]3 years ago
8 0

Answer:

C

Explanation:

APEX

marshall27 [118]3 years ago
5 0

Answer:

C. Hold polar molecules together.

Explanation:

This is just something you have to know.

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ElenaW [278]

Answer:

dont know, will let uk in 2 mins

Explanation:

3 0
3 years ago
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Sand dunes are created when the wind carrying the sand runs into an obstacle A. True B. False
Troyanec [42]

A. True

They are formed behind an obstacle when the wind blows the sand up to it.

3 0
3 years ago
What forms an electric current?
Kryger [21]
Electric current is electric charge in motion. It can take the form of a sudden discharge of static electricity, such as a lightning bolt or a spark between your finger and a ground light switch plate. ... Protons have positive charge, while electrons have negative charge. Hope this helps
5 0
3 years ago
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A pycnometer is a precisely weighted vessel that is used for highly accurate density determinations. Suppose that a pycnometer h
dexar [7]

Answer:

5.758  is the density of the metal ingot in grams per cubic centimeter.

Explanation:

1) Mass of pycnometer = M = 27.60 g

Mass of pycnometer with water ,m= 45.65 g

Density of water at 20 °C = d =998.2 kg/m^3

1 kg = 1000 g

1 m^3=10^6 cm^3

998.2 kg/m^3=\frac{998.2 \times 1000 g}{10^6 cm^3}=0.9982 g/cm^3

Mass of water ,m'= m - M = 45.65 g -  27.60 g =18.05 g

Volume of pycnometer = Volume of water present in it = V

Density=\frac{Mass}{Volume}

V=\frac{m'}{d}=\frac{18.05 g}{0.9982 g/cm^3}=18.08 cm^3

2) Mass of metal , water and pycnometer = 56.83 g

Mass of metal,M' =  9.5 g

Mass of water when metal and water are together ,m''= 56.83 g - M'- M

56.83 g - 9.5 g - 27.60 g = 19.7 g

Volume of water when metal and water are together = v

v=\frac{m''}{d}=\frac{19.7 g}{0.9982 g/cm^3}=19.73 cm^3

Density of metal = d'

Volume of metal = v' =\frac{M'}{d'}

Difference in volume will give volume of metal ingot.

v' = v - V

v'=19.73 cm^3-18.08 cm^3=

v'=1.65 cm^3

Since volume cannot be in negative .

Density of the metal =d'

=d'=\frac{M'}{v'}=\frac{9.5 g}{1.65 cm^3}=5.758 g/cm^3

5 0
3 years ago
Make the following conversion. 0.0097 mg = _____ g
Fynjy0 [20]
Your answer would be C

7 0
3 years ago
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