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tatyana61 [14]
3 years ago
7

Make the following conversion. 0.0097 mg = _____ g

Chemistry
2 answers:
Fynjy0 [20]3 years ago
7 0
Your answer would be C

kaheart [24]3 years ago
6 0

Answer: (A) 0.0000097

Explanation:

Grams and milligrams are the units of measurement of mass.

According to metric system:

1 g= 1000 mg

Thus 1mg=10^{-3}g

Given : 0.0097 g

Thus if 1 milli gram is equal to 10^-3}g

0.0097 g is equal to=\frac{10^{-3}}{1}\times 0.0097=0.0000097g

Thus the correct option is A.

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6 0
3 years ago
Once again if anyone could help, I would really appreciate your help! Thank you ❤️
Nikolay [14]

Answer:

D

Explanation:

I explained how to do it on your other problem so look there :)

6 0
3 years ago
Two solutions namely, 500 ml of 0.50 m hcl and 500 ml of 0.50 m naoh at the same temperature of 21.6 are mixed in a constant-pre
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24.6 ℃

<h3>Explanation</h3>

Hydrochloric acid and sodium hydroxide reacts by the following equation:

\text{HCl} \; (aq) + \text{NaOH} \; (aq) \to \text{NaCl} \; (aq) + \text{H}_2\text{O} \; (aq)

which is equivalent to

\text{H}^{+} \; (aq) + \text{OH}^{-} \; (aq) \to \text{H}_2\text{O}\; (l)

The question states that the second equation has an enthalpy, or "heat", of neutralization of -56.2 \; \text{kJ}. Thus the combination of every mole of hydrogen ions and hydroxide ions in solution would produce 56.2 \; \text{kJ} or 56.2 \times 10^{3}\; \text{J} of energy.

500 milliliter of a 0.50 mol per liter "M" solution contains 0.25 moles of the solute. There are thus 0.25 moles of hydrogen ions and hydroxide ions in the two 0.500 milliliter solutions, respectively. They would combine to release 0.25 \times 56.2 \times 10^{3} = 1.405 \times 10^{4} \; \text{J} of energy.

Both the solution and the calorimeter absorb energy released in this neutralization reaction. Their temperature change is dependent on the heat capacity <em>C</em> of the two objects, combined.

The question has given the heat capacity of the calorimeter directly.

The heat capacity (the one without mass in the unit) of water is to be calculated from its mass and <em>specific</em> heat.

The calorimeter contains 1.00 liters or 1.00 \times 10^{3} \; \text{ml} of the 1.0 gram per milliliter solution. Accordingly, it would have a mass of 1.00 \times 10^{3} \; \text{g}.

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