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3 years ago

Make the following conversion. 0.0097 mg = _____ g

Chemistry

2 answers:

Fynjy0 [20]3 years ago

7 0

Your answer would be C

kaheart [24]3 years ago

6 0

Answer: (A) 0.0000097

Explanation:

Grams and milligrams are the units of measurement of mass.

According to metric system:

1 g= 1000 mg

Thus $1mg=10^{-3}g$

Given : 0.0097 g

Thus if 1 milli gram is equal to $10^-3}g$

0.0097 g is equal to= $\frac{10^{-3}}{1}\times 0.0097=0.0000097g$

Thus the correct option is A.

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If 22.5 mol of an ideal gas occupies 30.5 L at 447 K, what is the pressure of the gas?

Fantom [35]

Answer:

P = 27.07 atm

Explanation:

Given that,

The number of moles, n = 22.5 mol

Volume, V = 30.5 L

Temperature, T = 447 K

We need to find the pressure of the gas. The ideal gas law is as follows :

$PV=nRT\\\\P=\dfrac{nRT}{V}$

R = 0.0821 L-atm/mol-K

Put all the values,

$P=\dfrac{22.5\times 0.0821\times 447}{30.5}\\\\P=27.07\ L$

So, the pressure of the gas is 27.07 atm.

8 0

3 years ago

A water bottling company is looking to achieve maximum production from the following reversible reaction. If the reaction has re

dybincka [34]

Answer:

Remove the already produced water and allow the reaction to reach equilibrium again.

Explanation:

<em>According to Le Chatelier principle, when a reaction is in equilibrium and one of the factors that influence the rate of reaction is altered, the equilibrium will shift so as to annul the effects of the change.</em>

If the product is continuously being removed from a reaction that is in equilibrium, more product will continued to be formed in another to annul the effect of reduction in the concentration of product.

Hence, in order to maximize production of water in the reaction, the product (water) needs to be removed and the reaction allowed to reach equilibrium again.

7 0

4 years ago

What atomic or hybrid orbitals make up the sigma bond between c2 and c3 in propyne, chcch3 ? (c2 is the second carbon in the str

Anvisha [2.4K]

Answer:

$\boxed{\text{$\sigma$(sp-sp$^{3}$); 180$^{\circ}$}}$

Explanation:

(a) Hybridization of orbitals

See the Lewis structure of propyne in the first diagram below.

C1 is directly bonded to two other atoms (H and C2) so it is sp hybridized.

C2 is directly bonded to two other atoms (C1 and C3) so it is sp hybridized.

C3 is directly bonded to four other atoms (C2 and 3 H) so it is sp³ hybridized.

(b) C2-C3 Sigma Bond

See the atomic and molecular orbitals in the second picture below.

C3 is using its hybrid atomic orbitals to form sigma molecular bonds. The C2-C3 sigma bond is formed by the overlap of the C2 sp atomic orbital with the C3 sp³ atomic orbital to make a σ(sp-sp³) molecular orbital.

C1 and C2 are sp hybridized. Since the angle between sp orbitals is 180°, all atoms directly attached the C1 and C2 must be in a straight line. The C-C-C bond angle is 180°.

4 0

3 years ago