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sveta [45]
2 years ago
9

NEED HELP ASAP!! ANSWER A THROUGH F PLEASE!!

Mathematics
1 answer:
Verdich [7]2 years ago
5 0

Answer:

A. 12

B. 4

C. 10

D. 8

E. 36

F. 70

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HELP IS THIS correct??? !!!
Allushta [10]

Answer:

No

Step-by-step explanation:

                                            x           y

y = - 3(-2) + 1 =  7                -2        7        

y = -3(0) +1 = 1                      0         1

y = -3(1) + 1 = -2                    1          -2

y = -3(3) + 1 = -8                   3      -8

8 0
3 years ago
Which expression is a cube root of -1+ i sqrt 3? (multiple choice)
lara31 [8.8K]

Answer:

see below

Step-by-step explanation:

Find the magnitude   (-1)^2  + (sqrt3)^2 = m^2   m = 2

find the angle    arctan (sqrt3/-1) = 120 degrees

the cube root would then be

\sqrt[3]{2}(cos 40 + isin 40)

6 0
1 year ago
Which is greater 36 yards and 2 feet or 114 feet and 2 inches
sp2606 [1]
114 feet and 2 inches
5 0
3 years ago
Read 2 more answers
Can a right triangle have a leg that is 10 meters long and a hypotenuse that is 10 meters long
pishuonlain [190]
Lets see
a and b are legs
c=hypotnuse
a^2+b^2=c^2
10^2+b^2=10^2
100+b^2=100
minus 100 both sides
b^2=0
b=0
false, if you have a leg legnth 0, then they lines are right on top of each other




no cannot
5 0
3 years ago
Read 2 more answers
Use the Binomial Theorem/Pascal's Triangle to expand (2a + 2b)^5
pochemuha

Answer:  

32a^5+160a^4b+320a^3b^2+320a^2b^3+160ab^4+32b^5

============================================================

Explanation:

Let's use Pascal's Triangle

In the row that starts with 1,5,... we have the values 1,5,10,10,5,1

These will be the coefficients of the terms.

Let x = 2a and y = 2b

We want to expand out (x+y)^5

Using pascals triangle, we get the following expansion

(x+y)^5 = 1x^5y^0+5x^4y^1+10x^3y^2+10x^2y^3+5x^1y^4+1x^0y^5

The numbers in bold are the coefficients 1,5,10,10,5,1 found earlier.

Note how the exponents for x start at 5 and count down to 0; while the y exponents start at 0 and count up to 5. For any term, the x and y exponents always add to 5 for the expansion of (x+y)^5. In general, the exponents of any term will add to n for (x+y)^n.

At this point, we plug in x = 2a and y = 2b

Since this will clutter things a bit, I'll do it term by term

  • 1x^5y^0 = 1(2a)^5(2b)^0 = 1(32a^5)(1) = 32a^5
  • 5x^4y^1 = 5(2a)^4(2b)^1 = 5(16a^4)(2b) = 160a^4b
  • 10x^3y^2 = 10(2a)^3(2b)^2 = 10(8a^3)(4b^2) = 320a^3b^2
  • 10x^2y^3 = 10(2a)^2(2b)^3 = 10(4a^2)(8b^3) = 320a^2b^3
  • 5x^1y^4 = 5(2a)^1(2b)^4 = 5(2a)(16b^4) = 160ab^4
  • 1x^0y^5 = 1(2a)^0(2b)^5 = 1(1)(32b^5) = 32b^5

So in the end, the expression (2a+2b)^5 expands out to

32a^5+160a^4b+320a^3b^2+320a^2b^3+160ab^4+32b^5

The binomial theorem uses the same basic idea, but instead of using Pascal's Triangle to get the coefficients, you'll use the nCr combination formula.

8 0
2 years ago
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