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3 years ago

What would be the number of oxygen atoms in 5.00 moles of co2?

Chemistry

1 answer:

malfutka [58]3 years ago

6 0

Well theres 5 so times 2 equals 10

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Approximately 2.5 kg of carbon dioxide gas are produced for every liter of gasoline burned in an automobile gasoline engine. Cal

uranmaximum [27]

125 mile *1gallon/35 mi = 135/35 = (27/7) gallon gasoline

27/7 gallon * 1 L/0.264 gallon = 14.6 L gasoline

14.6 L gasoline * 2.5kg CO2/1L gasoline= 36.5 kg CO2

36.5 kg CO2 * 1lb/0.454 kg = 80.4 lb

Answer: 80.4 lb CO2

6 0

3 years ago

cyclohexanol is burned as a fuel, according to the following equation, how many moles of oxygen are needed to produce 13.7 mol o

lidiya [134]

The moles of oxygen that are needed to produce 13.7 moles of carbon dioxide is 21.17 moles of Oxygen

<u><em>calculation</em></u>

2 C₆H₁₂O + 17 O₂ → 12 CO₂ +12 H₂O

The moles of O₂ is determined using the mole ratio

that is for given equation above O₂ : Co₂ is 17 :12

therefore the moles of O ₂= 13.7 moles x 17/12 =21.17 moles

3 0

3 years ago

Name 2 separate technique in separating iodine crystal and iron filings

KonstantinChe [14]

One is through sublimation, where the mixture is heated and iodine gets converted into gaseous form, leaving behind the iron fillings.

The other is to get a magnet near the mixture and all the iron fillings get attracted to it while iodine will be left over

5 0

3 years ago

What is the mass of 1.58 moles of CH4

HACTEHA [7]

<h3>Answer:</h3>

25.4 g CH₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.58 mol CH₄

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of CH₄ - 12.01 + 4(1.01) = 16.05 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 1.58 \ mol \ CH_4(\frac{16.05 \ g \ CH_4}{1 \ mol \ CH_4})$
Multiply/Divide: $\displaystyle 25.359 \ g \ CH_4$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

25.359 g CH₄ ≈ 25.4 g CH₄

4 0

3 years ago

I will give brainlyst for this so pls help

omeli [17]

Answer:

Answer -b

Explanation:

Brainliest pls

8 0

3 years ago

Read 2 more answers