1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
igomit [66]
3 years ago
13

A round, three dimensional object is a?

Chemistry
1 answer:
Dafna1 [17]3 years ago
6 0

Answer:

Sphere

Explanation:

No explanation

You might be interested in
Is Sr3(PO4)2 ionic or covalent
lana66690 [7]
Sr3(PO4)2 is definitely Ionic
6 0
3 years ago
Difference between nitrogen 14 and nitrogen 15
Tema [17]
Did you ever get this answer
5 0
3 years ago
Some hypothetical alloy is composed of 12. 5 wt% of metal a and 87. 5 wt% of metal b. If the densities of metals a and b are 4.
gavmur [86]

Answer:

The number of

atoms in the unit cell is 2

Explanation:

7 0
2 years ago
Air, with an initial absolute humidity of 0.016 kg water per kg dry air, is to be dehumidified for a drying process by an air co
amid [387]

Answer:

(a) The proportion of dry air bypassing the unit is 14.3%.

(b) The mass of water removed is 1.2 kg per 100 kg of dry air.

Explanation:

We can express the proportion of air that goes trough the air conditioning unit as p_{d} and the proportion of air that is by-passed as p_{bp}, being p_{d}+p_{bp}=1.

The amount of water that goes into the drier inlet has to be 0.004 kg/kg, and can be expressed as:

0.004 = 0.016*p_{bp}+ 0.002*p_{d}

Replacing the first equation in the second one we have

0.004 = 0.016*(1-p_{d})+ 0.002*p_{d}=0.016-0.016*p_{d}+0.002*p_{d}\\0.004 - 0.016 = (-0.016+0.002)*p_{d}\\-0.012 = -0.014*p_{d}\\p_{d}=\frac{-0.012}{-0.014}=0.857\\\\p_{bp}=1-p_{d}=1-0.857=0.143

(b) Of every kg of dry air feed, 85.7% goes in to the air conditioning unit.

It takes (0.016-0.002)=0.014 kg water per kg dry air feeded.

The water removed of every 100 kg of dry air is

100 kgDA*0.857*0.014 kgW/kgDA= 1.1998 \approx 1.2 kgW

It can also be calculated as the difference in humiditiy between the inlet and the outlet: (0.016-0.004=0.012 kgW/kDA) and multypling by the total amount of feed (100 kgDA).

100 * 0.012 = 1.2 kgW

7 0
3 years ago
How many unpaired electrons are in sulfur
12345 [234]

There are 2 unpaired electrons in sulphur orbital...


5 0
3 years ago
Read 2 more answers
Other questions:
  • Given the two reactions PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq), K3 = 1.84×10−10, and AgCl(aq)⇌Ag+(aq)+Cl−(aq), K4 = 1.14×10−4, what is the
    14·1 answer
  • Help I need to show work!
    10·1 answer
  • Chromosomes are<br> ??????
    14·1 answer
  • In general, how can the periodic trends displayed by elements be explained?
    11·1 answer
  • Is my answer correct?
    15·2 answers
  • Draw the products of Claisen condensation of (a) ethyl propanoate; (b) ethyl-3-methylbutanoate; (c) ethyl pentanoate. For each,
    15·1 answer
  • Which expression of distance uses SI units?
    15·1 answer
  • Carbonic acid (H₂CO₃) is a polyprotic acid. When carbonic acid dissolves in water, which is higher, the concentration of HCO₃- i
    9·1 answer
  • How many MOLECULES are in 50.0 grams of lithium phosphate?
    6·1 answer
  • Which of these statements is false?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!