Draw the products of Claisen condensation of (a) ethyl propanoate; (b) ethyl-3-methylbutanoate; (c) ethyl pentanoate. For each,
the base used is sodium ethoxide and the solvent is ethanol.
1 answer:
Answer:
Structures of products has been shown below
Explanation:
- In claisen condensation, two ester molecules combines with each other through nucleophilic acyl substitution resulting formation of a
-ketoester.
- At first, one ester molecule gets deprotonated in presence of a strong base e.g. NaOEt yielding a carbanion.
- The carbanion then gives nucleophilic acyl substitution reaction with another ester molecule to replace alkoxy group present in ester group
- General reaction mechanism of claisen condensation along with products of given esters are shown below.
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Taking into account the reaction stoichiometry, 340.0 moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
CO₂ + 4 H₄ → CH₄ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- CO₂: 1 mole
- H₄: 4 moles
- CH₄: 1 mole
- H₂O: 2 moles
The following rule of three can be applied: if by reaction stoichiometry 1 mole of CO₂ form 4 moles of CH₄, 85.1 moles of CO₂ form how many moles of CH₄?
<u><em>moles of CH₄= 340.4 moles</em></u>
Then, 340.0 moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas
Learn more about the reaction stoichiometry:
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