Draw the products of Claisen condensation of (a) ethyl propanoate; (b) ethyl-3-methylbutanoate; (c) ethyl pentanoate. For each,
the base used is sodium ethoxide and the solvent is ethanol.
1 answer:
Answer:
Structures of products has been shown below
Explanation:
- In claisen condensation, two ester molecules combines with each other through nucleophilic acyl substitution resulting formation of a
-ketoester.
- At first, one ester molecule gets deprotonated in presence of a strong base e.g. NaOEt yielding a carbanion.
- The carbanion then gives nucleophilic acyl substitution reaction with another ester molecule to replace alkoxy group present in ester group
- General reaction mechanism of claisen condensation along with products of given esters are shown below.
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Molarity after dilution : 0.0058 M
<h3>Further explanation </h3>The number of moles before and after dilution is the same
The dilution formula
M₁V₁=M₂V₂
M₁ = Molarity of the solution before dilution
V₁ = volume of the solution before dilution
M₂ = Molarity of the solution after dilution
V₂ = Molarity volume of the solution after dilution
M₁=0.1 M
V₁=6.11
V₂=105.12