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Vlada [557]
3 years ago
15

Draw the products of Claisen condensation of (a) ethyl propanoate; (b) ethyl-3-methylbutanoate; (c) ethyl pentanoate. For each,

the base used is sodium ethoxide and the solvent is ethanol.

Chemistry
1 answer:
Nonamiya [84]3 years ago
5 0

Answer:

Structures of products has been shown below

Explanation:

  • In claisen condensation, two ester molecules combines with each other through nucleophilic acyl substitution resulting formation of a \beta-ketoester.
  • At first, one ester molecule gets deprotonated in presence of a strong base e.g. NaOEt yielding a carbanion.
  • The carbanion then gives nucleophilic acyl substitution reaction with another ester molecule to replace alkoxy group present in ester group
  • General reaction mechanism of claisen condensation along with products of given esters are shown below.

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vova2212 [387]

Answer:

Q = -18118.5KJ

W = -18118.5KJ

∆U = 0

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Explanation:

W = RTln(P1/P2)

P1 = 1bar = 100KN/m^2, P2 = 1500bar = 1500×100 = 150000KN/m^2, T = 23°C = 23 + 273K = 298K

W = 8.314×298ln(100/150000) = 8.314×298×-7.313 = -18118.5KJ ( work is negative because the isothermal process involves compression)

∆U = Cv(T2 - T1)

For an isothermal process, temperature is constant, so T2 = T1

∆U = Cv(T1 - T1) = Cv × 0 = 0

Q = ∆U + W = 0 + (-18118.5) = 0 - 18118.5 = -18118.5KJ

∆H = Cp(T2 - T1)

T2 = T1

∆H = Cp(T1 - T1) = Cp × 0 = 0

∆S = Q/T

Mass of water = 1kg

Heat transferred (Q) per kilogram of water = -18118.5KJ/Kg

∆S = (-18118.5KJ/Kg)/298K = -60.80KJ/KgK

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Answer:

\large \boxed{\sf metal \ and \ non \ metal}

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elena-14-01-66 [18.8K]
We are given the equation to use which is:
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We are also given that:
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Substitute with these givens in the above equation to get ΔS as follows:
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Based on the above calculations, the correct choice is:
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