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Vlada [557]
3 years ago
15

Draw the products of Claisen condensation of (a) ethyl propanoate; (b) ethyl-3-methylbutanoate; (c) ethyl pentanoate. For each,

the base used is sodium ethoxide and the solvent is ethanol.

Chemistry
1 answer:
Nonamiya [84]3 years ago
5 0

Answer:

Structures of products has been shown below

Explanation:

  • In claisen condensation, two ester molecules combines with each other through nucleophilic acyl substitution resulting formation of a \beta-ketoester.
  • At first, one ester molecule gets deprotonated in presence of a strong base e.g. NaOEt yielding a carbanion.
  • The carbanion then gives nucleophilic acyl substitution reaction with another ester molecule to replace alkoxy group present in ester group
  • General reaction mechanism of claisen condensation along with products of given esters are shown below.

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Explanation:

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Calculate the Molarity when a 6.11 mL solution of 0.1 H2SO4 is diluted with 105.12 mL of water
barxatty [35]

Molarity after dilution : 0.0058 M

<h3>Further explanation </h3>

The number of moles before and after dilution is the same  

The dilution formula

 M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = Molarity volume of the solution after dilution

M₁=0.1 M

V₁=6.11

V₂=105.12

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Answer:

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Explanation:

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