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3 years ago

12

If you push a book against a wall hard enough it will not slide down even though gravity is pulling it. Use what you know about

friction and newtons laws of motion to explain why the book does not fall

1 answer:

e-lub [12.9K]3 years ago

3 0

Yes the book will fall on the floor

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In a polytropic process, with the exponent n = k, where k is the specific heat ratio, 1.0 kg of neon (an ideal gas) in a frictio

Elden [556K]

A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs.
Read more on Brainly.com - brainly.com/question/1581851#readmore

3 0

3 years ago

A car starts from rest and accelerates with a constant acceleration of 1.00 m/s2 for 3.00 s. The car continues for 5.00 s at con

barxatty [35]

Answer:

19.5 m

Explanation:

Using the equation of motion,

For the first 3 seconds,

s = ut +1/2at².......................... Equation 1

Where t = time, u = initial velocity, a = acceleration, s = distance

Note: Since the car starts from rest, u = 0 m/s.

Given: a = 1.0 m/s, t = 3 s, u = 0 m/s

Substitute into equation 1

s = 0×3+1/2(3)²(1)

s = 9/2

s = 4.5

In the remaining five seconds, at a constant velocity,

s' = vt............. Equation 2

Where v = velocity, t = time.

Recall,

v = u+at

v = 0+1(3)

v = 3 m/s.

Also, t = 5 s.

Substitute into equation 2

s' = 3(5)

s' = 15 m.

Total distance = 15+4.5

Total distance = 19.5 m.

Hence the car travels 19.5 m

8 0

3 years ago

Currently, the Sun is thought to be located in the galactic _____________ about ____________ the center of the galaxy.

Ede4ka [16]

Answer:

a. Disk, 28 thousand light-years from

Explanation:

Since, a galactic disc is a component of disc galaxies, for instance spiral galaxies and lenticular galaxies. It consists of a stellar component and a gaseous component.

Also, the Sun lies within the galactic disk or in other words it is thought to be located in the galactic disk,

The Sun is located about 26,000 light-years away from the centre of the galaxy.

∵ From the given options 28,000 is nearest to 26,000

Hence, the sun is about 28 thousand light-years from the centre of the galaxy.

i.e. OPTION 'a' would be correct.

8 0

3 years ago

The hydrocarbon C2H4 is a member of the_series.

Darina [25.2K]

Answer:

alkene series

Explanation:

the alkene series are the hydrocarbons e.gc2h4 c3h8

8 0

3 years ago

Read 2 more answers

A single-turn current loop, carrying a current of 4.03 A, is in the shape of a right triangle with sides 68.1, 151, and 166 cm.

SashulF [63]

Answer:

Part a)

$F = 0$

Part b)

$F = 0.25 N$

Part c)

$F = 0.25 N$

Part d)

Net force on a closed loop in uniform magnetic field is always ZERO

$F_{net} = 0$

Explanation:

As we know that force on a current carrying wire is given as

$\vec F = i(\vec L \times \vec B)$

now we have

Part a)

current in side 166 cm and magnetic field is parallel

so we have

$F = i(\vec L \times \vec B)$

here we know that L and B is parallel to each other so

$F = 0$

Part b)

For 68.1 cm length wire we have

$F = iLB sin\theta$

here we know that

$cos\theta = \frac{68.1}{166}$

$\theta = 65.8$

so we have

$F = (4.03)(0.681)(99.3 \times 10^{-3})sin65.8$

$F = 0.25 N$

Part c)

For 151 cm length wire we have

$F = iLB sin\phi$

here we know that

$cos\phi = \frac{151}{166}$

$\theta = 24.5$

so we have

$F = (4.03)(1.51)(99.3 \times 10^{-3})sin24.5$

$F = 0.25 N$

Part d)

Net force on a closed loop in uniform magnetic field is always ZERO

$F_{net} = 0$

4 0

2 years ago