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bagirrra123 [75]
3 years ago
9

What is the speed of a truck that travels 10 i’m in 10 minutes ?

Physics
1 answer:
fiasKO [112]3 years ago
7 0

10km/10min is a legitimate speed. So is meters/sec, km/hour (kph), etc.  

Kph is very common for vehicles:  

10 km/10 min (60 min/hr) = 60 kph

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A force of 1 newton will cause a mass of 1 kg to have an acceleration of 1 m/s^2. If a force of 5 newtons is applied to a mass o
nignag [31]

For any force and any mass, the acceleration is always

(the strength of the force) divided by (the mass) .

If a force of 5 newtons is applied to a mass of 5 kg, the acceleration will be

(5 Newtons) / (5 kg) = <em>1 m/s²</em>

7 0
3 years ago
A car traveling at 12 m/s slows down with an acceleration of -1.5 m/s2. What is the
Alex777 [14]

Answer:

using s=ut +0.5at^2

u=12m/s

a=-1.5m/s2

t=6 s

s=54m

7 0
2 years ago
An object is moving due north at 31m/s. Does this tell you the speed of the velocity of the object or both?
dsp73

Answer:

speed

Explanation:

its the speed

because the formula for deriving speed is distance/time

the unit for distance is metre

the unit for time is seconds

so speed is metre/seconds

so speed us m/s.

7 0
2 years ago
A light beam strikes a piece of glass at a 65.00 ∘ incident angle. The beam contains two wavelengths, 450.0 nm and 700.0 nm, for
Leokris [45]

Answer:

Explanation:

Lower the refractive index ,  higher the wave length

Refractive index becoming high reduces the velocity and hence wavelength as frequency remains unchanged.

So refractive index  1.4831 will correspond to wavelength of 450 nm.

For  refractive index is 1.4831 , angle of incidence i , angle of refraction r .

Sin i / Sinr = 1.4831

sin65 / sinr = 1.4831

sir r = sin65 / 1.4831

= .9063 / 1.4831

= .6111

r = 37.67 degree

For  refractive index is 1.4754 , angle of incidence i

Sin i / Sinr = 1.4754

sin65 / sinr = 1.4754

sir r = sin65 / 1.4754

= .9063 / 1.4754

= .61427

r = 37.9 degree

angle between two refracted ray

37.9 -37.67

= 0. 23 degree

6 0
2 years ago
Read 2 more answers
Calculate the magnetic field strength needed on a 170-turn square loop 22 cm on a side to create a maximum torque of 295 N·
Triss [41]

Answer:

B = 1.823 T.

Explanation:

Given,

Number of turns,N = 170 turn

Side of square loop,L = 22 cm

Maximum torque, τ = 295 N.m

Current on the loop, I = 20 A

Magnetic strength =  ?

Torque = N BIA

300 = 170 x  B x 20 x  0.22²

300 = 164.56 B

B = 1.823 T.

Hence, the magnetic field strength is equal to B = 1.823 T.

7 0
2 years ago
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