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Ronch [10]
3 years ago
14

Can someone explain subshell/electron configuration to me?

Physics
1 answer:
Anastasy [175]3 years ago
6 0
There are four layers of these electrons are, s, p, d, and f.

Each one has a certain number of shells, in different shapes, that can hold two electrons.

S- Has one shell, shaped like a circle, so in total can hold 2 electrons.

P- has three shells, shaped like an infinity symbol, so in total can hold 6 electrons

D- has five shells, shaped, err, dunno how to describe it, can hold 10 electrons.

F- has 7 shells, um, even more dunno how to describe it, can hold 14 electrons

There doesn't only have to be one of each shell though. There can be two S levels, and one P level, and no D or F levels.

(search up electron configuration it'll have a chart of the order in which these come in)

Each layer will be stated as Number layer electron number.

For example, the first layer of electron level would be 1, because it's the first layer, S, because that's what the first layer is, and if it was completely filled, 2.

So, 1s2.

If you were going to add another level, which would also be a S level, but it only has one electron, you would say:

2s1,

because it's the second s level and has one electron in it.

And to put the two together, just say:

1s2, 2s1

NOTE: if you were going to add another level, it would be a P level, but it wouldn't be 3p something, it would be 1p something because it is the first electron level.

Another note: if you have three layers of electrons, or just six electrons, you would just say 1p6. (because the P orbital can hold 6 electrons)

Hope this helped!
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When a satellite is a distance R from the center of the Earth, the force of gravity on the satellite is F. What is the gravitati
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Gravitational force on a satellite is given by the formula

F = \frac{GMm}{r^2}

now here we know that force on the satellite is F when its distance from center of Earth is R

Now the distance from the center of earth will be 3R so the force is given as

F' = \frac{GMm}{(3R)^2}

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Which is a characteristic of the image formed by an
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The image is virtual.

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Speed in any given direction is called <br> A. Trust<br> B.velocity<br> C.mass<br> D.acceleration
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A rocket takes off from Earth's surface, accelerating straight up at 47.2 m/s2. Calculate the normal force (in N) acting on an a
lions [1.4K]

Answer:

Approximately 4.61\times 10^{3}\; {\rm N} upwards (assuming that g = 9.81\; {\rm m\cdot s^{-2}}.)

Explanation:

External forces on this astronaut:

  • Weight (gravitational attraction) from the earth (downwards,) and
  • Normal force from the floor (upwards.)

Let (\text{normal force}) denote the magnitude of the normal force on this astronaut from the floor. Since the direction of the normal force is opposite to the direction of the gravitational attraction, the magnitude of the net force on this astronaut would be:

\begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned}.

Let m denote the mass of this astronaut. The magnitude of the gravitational attraction on this astronaut would be (\text{weight}) = m\, g.

Let a denote the acceleration of this astronaut. The magnitude of the net force on this astronaut would be (\text{net force}) = m\, a.

Rearrange \begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned} to obtain an expression for the magnitude of the normal force on this astronaut:

\begin{aligned}(\text{normal force}) &= (\text{net force}) + (\text{weight}) \\ &= m\, a + m\, g \\ &= m\, (a + g) \\ &= 80.9\; {\rm kg} \times (47.2\; {\rm m\cdot s^{-2}} + 9.81\; {\rm m\cdot s^{-2}}) \\ &\approx 4.61 \times 10^{3}\; {\rm N}\end{aligned}.

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2 years ago
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