Answer:
45 W
Explanation:
First of all, we need to find the work done by the person to lift the bag. The work done is given by

where
F = 75.0 N is the force applied
d = 1.50 m is the displacement of the bag
Substituting numbers into the formula,

Now we can find the power used, which is given by

where
t = 2.50 s is the time taken
Again, using W=112.5 J, we find

The coefficient of kinetic friction (μ) between the block and the table is 0.4.
<h3>
What is kinetic friction?</h3>
This sis the frictional force between an object in motion with the surface in contact.
μN = ff
where;
- N is normal reaction due to weight of the block
- ff is frictional force
- μ is coefficient of friction
μ = ff/N
μ = 8/20
μ = 0.4
Thus, the coefficient of kinetic friction (μ) between the block and the table is 0.4.
Learn more about coefficient of friction here: brainly.com/question/20241845
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<em>H</em> is the location of the Japanese nuclear power plant at Fkushima and <em>I</em> is the location of the Ukraine accident in Chernobyl. At the time, Chernobyl was part of the USSR, but that country no longer exists. These meltdowns will leave the area radioactive for many more years.
Answer:
a. 1.5 m/s
Explanation:
We will apply the law of conservation of energy in this situation between the initial position and the lowest point of the swing:

where,
m₁ = mass of ball = 1.6 kg
m₂= mass of block = 0.8 kg
u₁ = initial speed of ball = 0 m/s
u₂ = initial speed of block = 0 m/s
v₁ = final speed of ball = ?
v₂ = final speed of block = 3 m/s
Therefore,

v₁ = 1.5 m/s
Therefore, the correct option is:
<u>a. 1.5 m/s</u>