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2 answers:
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Answer:(a)360N,(b)171N,(c)2.702m
Explanation:
(a)Maximum Friction Force =
=360 N
(b)Moment about Ground Point
(c)
Here maximum friction force can be 360 N
Therefore
Where x is the maximum distance moved by man along the ladder
740x=2000
x=2.702m
The force involved is = 25200 Newton
Given the values in the questions,
Mass = 1400 kg
Speed or velocity of the car = 27 m/s
Time is given = 1.5 seconds
According to the formula of force,
⇒ Force = Mass x Acceleration
⇒ Force = 1400 x Acceleration ----- equation 1
Now to calculate the value of acceleration we will use,
⇒ Acceleration = (Velocity or Speed) / Time
⇒ Acceleration = 27 / 1.5
⇒ Acceleration = 18 m/
Putting the value of acceleration in equation 1,
⇒ Force = 1400 x 18
⇒ Force = 25200 Newton
Therefore, the force involved is = 25200 Newton
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