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2 years ago

Please help me with this assignment!

Physics

2 answers:

makkiz [27]2 years ago

5 0

Answer:

lol you got the answer just need points sorry

Explanation:

Licemer1 [7]2 years ago

3 0

Answer:

Ice cube, molecules, melting, zero degrees, liquid, faster, temperature, 100 degrees, steam

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D). energy resulting from the attraction between two masses.

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A 75.0 kg driver slides into a seat in a truck that has only 1 spring. The spring compresses 1.60 cm = 0.0160 m. What is the spr

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A plane traveling north at 100.0 km/h through the air gets caught in a 40.0 km/h crosswind blowing west. This turbulence caused

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The velocity $\vec{v}_{c/g}$ of the cart with respect to the ground is

$\vec{v}_{c/g}=-40\hat{x}+80\hat{y}\, km/h$

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Explanation:

We have for relative motion the following expression:

$\vec{v}_{c/g}=\vec{v}_{c/p}+\vec{v}_{p/g}$

Where $\vec{v}_{c/g}$ is the velocity of the cart with respect to the ground, $\vec{v}_{c/p}$ is the velocity of the cart with respect to the plane and $\vec{v}_{p/g}$ is the velocity of the plane with respect to the ground.

We find that:

$\vec{v}_{c/p}=-20\hat{y}$

$\vec{v}_{p/g}=-40\hat{x}+100\hat{y}$

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$\vec{v}_{c/g}=-20\hat{y}-40\hat{x}+100\hat{y}=-40\hat{x}+80\hat{y} \, km/h$

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A 0.5 m diameter wagon wheel consists of a thin rim having a mass of 7 kg and six spokes, each with a mass of 1.2 kg. 1.2 kg 7 k

Arte-miy333 [17]

Explanation:

It is given that,

Mass of the rim of wheel, m₁ = 7 kg

Mass of one spoke, m₂ = 1.2 kg

Diameter of the wagon, d = 0.5 m

Radius of the wagon, r = 0.25 m

Let I is the the moment of inertia of the wagon wheel for rotation about its axis.

We know that the moment of inertia of the ring is given by :

$I_1=m_1r^2$

$I_1=7\times (0.25)^2=0.437\ kgm^2$

The moment of inertia of the rod about one end is given by :

$I_2=\dfrac{m_2l^2}{3}$

l = r

$I_2=\dfrac{m_2r^2}{3}$

$I_2=\dfrac{1.2\times (0.25)^2}{3}=0.025\ kgm^2$

For 6 spokes, $I_2=0.025\times 6=0.15\ kgm^2$

So, the net moment of inertia of the wagon is :

$I=I_1+I_2$

$I=0.437+0.15=0.587\ kgm^2$

So, the moment of inertia of the wagon wheel for rotation about its axis is $0.587\ kgm^2$ . Hence, this is the required solution.

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