All categories

4 years ago

What is the percent by mass in a solution with 10.0 grams of solute and 25.0 grams of solvent?

Chemistry

1 answer:

rewona [7]4 years ago

4 0

Answer:

Percent by mass of solute is (10/35) x 100 = 28.57%

Percent by mass of solvent is (25/35) x 100 = 71.43%

Explanation:

10.0 grams of solute

25.0 grams of solvent

Total Mass = 35 grams

percent by mass = (Mass A / Total Mass) x 100

Percent by mass of solute is (10/35) x 100 = 28.57%

Percent by mass of solvent is (25/35) x 100 = 71.43%

You might be interested in

How many moles of gas does it take to occupy 120 L at a pressure of 233 kPa and a temperature of 340 K?

natka813 [3]

A would be correct have a nice day.

5 0

3 years ago

Read 2 more answers

Drive down any three characteristic of modern periodic table

Nitella [24]

Electronegativity
Atomic radius
Ionization energy

6 0

3 years ago

Germanium is a group 4A semiconductor. The addition of a dopant atom (group 3A element) that has fewer valence electrons than th

klasskru [66]

Answer:

Doping with galium or indium will yield a p-type semiconductor while doping with arsenic, antimony or phosphorus will yield an n-type semiconductor.

Explanation:

Doping refers to improving the conductivity of a semiconductor by addition of impurities. A trivalent impurity leads to p-type semiconductor while a pentavalent impurity leads to an n-type semiconductor.

7 0

3 years ago

A mixture contains NaHCO3 together with unreactive components. A 1.75 g sample of the mixture reacts with HA to produce 0.561 g

Lynna [10]

Answer:

$\%NaHCO_3=61.2\%$

Explanation:

Hello.

In this case, since the undergoing chemical reaction is only between the sodium bicarbonate and the acid HA:

$NaHCO_3+HA\rightarrow NaA+H_2O+CO_2$

For 0.561 g of yielded carbon dioxide (molar mass 44 g/mol), the following mass of sodium bicarbonate (molar mass 84 g/mol) that reacted was:

$m_{NaHCO_3}=0.561gCO_2*\frac{1molCO_2}{44gCO_2} *\frac{1molNaHCO_3}{1molCO_2} *\frac{84gNaHCO_3}{1molNaHCO_3} \\\\m_{NaHCO_3}=1.071g$

Considering the 1:1 mole ratio between CO2 and NaHCO3. Finally, the percent by mass of NaHCO3 is computed by dividing the mass of reacted NaHCO3 and t the mixture:

$\%NaHCO_3=\frac{1.071g}{1.75g}*100\%\\ \\\%NaHCO_3=61.2\%$

Best regards.

5 0

3 years ago

Which shows the potential energy of particles in three substances, from least to greatest? liquid, solid, gas liquid, gas, solid

AleksandrR [38]

Answer:

Gas liquid solid

Explanation:

gases have a weak potential since they have a weak bond between molecules while in solids it's the strongest making them vibrate in a fixed position

3 0

3 years ago