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3 years ago

What is the percent by mass in a solution with 10.0 grams of solute and 25.0 grams of solvent?

Chemistry

1 answer:

rewona [7]3 years ago

4 0

Answer:

Percent by mass of solute is (10/35) x 100 = 28.57%

Percent by mass of solvent is (25/35) x 100 = 71.43%

Explanation:

10.0 grams of solute

25.0 grams of solvent

Total Mass = 35 grams

percent by mass = (Mass A / Total Mass) x 100

Percent by mass of solute is (10/35) x 100 = 28.57%

Percent by mass of solvent is (25/35) x 100 = 71.43%

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A calorie is another term for carbohydrate.TF

Hunter-Best [27]

<span>This is false. A carbohydrate is a carbon-based molecule that can be utilized by living organisms in order to produce energy. A calorie is a unit of energy often used to measure the amount of energy within food. Another example of energy unit is the Joule, more commonly used within physics.</span>

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2 years ago

Assuming that an acetic acid solution is 12% by mass and that the density of the solution is 1.00 g/mL, what volume of 1 M NaOH

Doss [256]

Explanation:

Let us assume that total mass of the solution is 100 g. And, as it is given that acetic acid solution is 12% by mass which means that mass of acetic acid is 12 g and 88 g is the water.

Now, calculate the number of moles of acetic acid as its molar mass is 60 g/mol.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{12 g}{60 g/mol}$

= 0.2 mol

Molarity of acetic acid is calculated as follows.

Density = $\frac{mass}{volume}$

1 g/ml = $\frac{100 g}{volume}$

volume = 100 ml

Hence, molarity = $\frac{\text{no. of moles}}{volume}$

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= 2 mol/l

As reaction equation for the given reaction is as follows.

$NaOH + CH_{3}COOH \rightarrow CH_{3}COONa + H_{2}O$

So, moles of NaOH = moles of acetic acid

Let us suppose that moles of NaOH are "x".

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x = 20 L

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3 years ago

what is moltarity of a solution made from dissolving 3.0 moles of saline (NaCl) in 0.25 L of solution

stiks02 [169]

It is 12 to 1 or 12/1 miles of saline to L solution

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2 years ago

The side chain (R group) of the amino acid serine is CH₂OH. The side chain of the amino acid leucine is CH₂CH(CH₃)₂. Where would

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Answer:

The answer is B, Alanine would be in the interior and serine would be on the exterior of the globular protein.

Explanation:

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This is why Alanine would be in the interior and serine would be on the exterior of the globular protein.

Cheers!

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