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Lerok [7]
3 years ago
7

The kingdom, protista, includes

Chemistry
2 answers:
s344n2d4d5 [400]3 years ago
5 0

Answer:

The answer is D most single-celled eukaryotes.

Explanation:

lyudmila [28]3 years ago
3 0
<span>The kingdom, protista’s characteristics are that the organism (not a plant, animal or fungus) are: unicellular however some are multicellular like algae, are heterotrophic or autotrophic, others lives in water while some live in moist areas or human body, have a nucleus, cellular respiration is primarily aerobic, some are pathogenic (e.g. causing Malaria) and reproduction is mitosis or meiosis. This kingdom includes: Sacordinians – pseudopods (e.g. Amoeba, Foraminiferans<span>.)</span>, Zooflagellates – flagellates (e.g. Trypanosoma gambiense), Ciliaphorans – ciliates (e.g. paramecium) and Sporozoans (e.g. Plasmodium).</span>
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Which term refers to compounds that can form hydrates but do not contain water molecules?
Lerok [7]
The term that refers to compounds that can form hydrates but do not contain water molecules is anhydrous.
6 0
3 years ago
Read 2 more answers
Name the five methods used for the formation of salts??
Viefleur [7K]

Explanation:

In chemistry, a salt is a chemical compound consisting of an ionic assembly of cations and anions.[1] Salts are composed of related numbers of cations (positively charged ions) and anions (negatively charged ions) so that the product is electrically neutral (without a net charge). These component ions can be inorganic, such as chloride (Cl−), or organic, such as acetate (CH

3CO−

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5 0
3 years ago
What is the average atomic mass of hafnium given the following abundance information on the isotopes?
Goryan [66]

Answer:

178.55

Explanation:

176 × 0.05+ 177 × 0.19 + 178 × 0.27 + 179 × 0.14 + 180 × 0.35 = 178.55

7 0
3 years ago
Hey! I was wondering how to get the solution to this question!
zzz [600]

Answer:

6.22 × 10⁻⁵

Explanation:

Step 1: Write the dissociation reaction

HC₆H₅COO ⇄ C₆H₅COO⁻ + H⁺

Step 2: Calculate the concentration of H⁺

The pH of the solution is 2.78.

pH = -log [H⁺]

[H⁺] = antilog -pH = antilog -2.78 = 1.66 × 10⁻³ M

Step 3: Calculate the molar concentration of the benzoic acid

We will use the following expression.

Ca = mass HC₆H₅COO/molar mass HC₆H₅COO × liters of solution

Ca = 0.541 g/(122.12 g/mol) × 0.100 L = 0.0443 M

Step 4: Calculate the acid dissociation constant (Ka) for benzoic acid

We will use the following expression.

Ka = [H⁺]²/Ca

Ka = (1.66 × 10⁻³)²/0.0443 = 6.22 × 10⁻⁵

3 0
3 years ago
How to apply Raoult's law to real solutions Consider mixing a liquid with a vapor pressure of 100 torr with an equimolar amount
garri49 [273]

Answer:

\boxed{\text{positive deviation}}

Explanation:

\text{If the molecules interact less favourably in the solution than in the individual}\\\text{liquids, they can break away more easily than they can in the separate liquids.}\\\text{There will be more molecules in the vapour phase than you would expect.}\\\text{The solution will show a } \boxed{\textbf{positive deviation}} \text{ from Raoult's Law.}

4 0
3 years ago
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