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-Dominant- [34]
3 years ago
5

Propose a method for determining the specific heat for a metal like sodium which reacts violently with water.

Chemistry
1 answer:
nalin [4]3 years ago
4 0
You can put a known amount sodium into some sort of time release mechanism such as a pill made from soluble material.  Then you can place the sodium into a calorimeter with a known mass of water and record the temperature change the water undergoes during the reaction.  Then you can use the equation q(water)=m(water)c(water)ΔT to find the amount of heat absorbed by the water.  since the amount of heat absorbed by the water is the amount of heat released from the sodium, q(sodium)=-q(water).  Than you can use the equation q(sodium)=m(sodium)c(sodium)ΔT and solve for c(sodium)

I hope this helps and feel free to ask about anything that was unclear in the comments.
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Answer:

588.2 mL

Explanation:

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First we <u>calculate how many Fe⁺² moles reacted</u>, using the given <em>concentration and volume of FeSO₄ solution</em> (the number of FeSO₄ moles is equal to the number of Fe⁺² moles):

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  • 187 mL * 0.692 M = 129.404 mmol Fe⁺²

Then we convert Fe⁺² moles to KOH moles, using the stoichiometric ratios:

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Finally we<u> calculate the required volume of KOH solution</u>, using <em>the given concentration and the calculated moles</em>:

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  • 258.808 mmol KOH / 0.440 M = 588.2 mL
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