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-Dominant- [34]
3 years ago
5

Propose a method for determining the specific heat for a metal like sodium which reacts violently with water.

Chemistry
1 answer:
nalin [4]3 years ago
4 0
You can put a known amount sodium into some sort of time release mechanism such as a pill made from soluble material.  Then you can place the sodium into a calorimeter with a known mass of water and record the temperature change the water undergoes during the reaction.  Then you can use the equation q(water)=m(water)c(water)ΔT to find the amount of heat absorbed by the water.  since the amount of heat absorbed by the water is the amount of heat released from the sodium, q(sodium)=-q(water).  Than you can use the equation q(sodium)=m(sodium)c(sodium)ΔT and solve for c(sodium)

I hope this helps and feel free to ask about anything that was unclear in the comments.
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nordsb [41]

Answer : The correct option is, (D) Be^{2+}

Explanation :

Effective nuclear charge : It is defined as the attraction of the protons present in the nucleus of an atom to the outermost electrons.

For ions, the effective nuclear charge changes than the neutral atom.

There are two types of ions:

Cations: They are formed when an atom looses its valence electrons. They are positive ions.

Anions: They are formed when an atom gain electrons in its outermost shell. They are negative ions.

For positive ions, the removal of electron increases the nuclear charge for an outermost electron because the outermost electrons are more strongly attracted by the nucleus. Thus, the effective nuclear charge increases for cations.

From this we conclude that, the size of the cation is smaller than their neutral atom because it has less number of electrons while its nuclear charge remains the same. So, the nucleus attracts the electron more towards itself and leads to the decrease in size.

For negative ions, the addition of electron decreases the nuclear charge for an outermost electron because the outermost electrons are less strongly attracted by the nucleus. Thus, the effective nuclear charge decreases for anions.

From this we conclude that, the size of the anion is greater than their neutral atom because it has more number of electrons while its nuclear charge remains the same. So, the nucleus attracts the electron less towards itself and leads to the increase in size.

Thus, the increasing order of radius of ions will be:

Be^{2+}

Hence, the smallest radius of ion is, Be^{2+}

4 0
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Ir = [Xe] 4f14 5d7 6s2 
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<span>Fe = [Ar] 3d6 4s2 </span>
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<span>Y = [Kr] 4d1 5s2 </span>
<span>Re = [Xe] 4f14 5d5 6s2 </span>
<span>So only Rhenium (Re) has an electronic configuration where the d orbital has 5 electrons in it.</span>
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