(missing part of your question):
when we have K = 1 x 10^-2 and [A] = 2 M & [B] = 3M & m= 2 & i = 1
So when the rate = K[A]^m [B]^i
and when we have m + i = 3 so the order of this reaction is 3 So the unit of K is L^2.mol^-2S^-1
So by substitution:
∴ the rate = (1x 10 ^-2 L^-2.mol^-2S^-1)*(2 mol.L^-1)^2*(3mol.L^-1)
= 0.12 mol.L^-1.S^-1
Answer:
If the zero is between fwo nonzeros
Explanation:
Answer:
A sample of an ideal gas has a volume of 2.21 L at 279 K and 1.01 atm. Calculate the pressure when the volume is 1.23 L and the temperature is 299 K.
You need to apply the ideal gas law PV=nRT
You have the pressure, P=1.01 atm
you have the volume, V = 2.21 L
The ideal gas constant R= 0.08205 L. atm/ mole.K at 273 K
find n = PV/RT = (1.01 atm x 2.21 L / 0.08205 L.atm/ mole.K x 273 K)
n= 0.1 mole, Now find the pressure for n=0.1 mole, T= 299K and
L=1.23 L
P=nRT/V= 0.1mole x 0.08205 (L.atm/ mole.K x 299 k)/ 1.23 L
= 1.994 atm
Explanation:
Answer:
The Answer is D: A solid with no repeating pattern in its structure
Explanation:
More unstable an electron configuration , the more reactive an atom will become.
How electron configuration influences the chemical behavior of an atom?
This is happen generally, If we look at the Group 1 elements in the periodic table, they are all highly reactive as they have 1 electron in their outermost shells - an unstable configuration in terms of energy.
Also, the noble gases in Group 8 in the periodic table are 'inert' that means they don't react (or more correctly, have an incredibly low reactivity). This is because they have 8 electrons in their outermost shell and thus have no need to acquire or lose electrons to possess a stable electron configuration.
Hence, electron configuration influences the chemical behavior of an atom.
learn more about electronic configuration here :
brainly.com/question/26084288
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