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swat32
3 years ago
7

A solid metal ball and a hollow plastic ball of the same external radius are released from rest in a large vacuum chamber. When

each has fallen 1 m, they both have the same?
Physics
1 answer:
S_A_V [24]3 years ago
5 0

Answer:

time of fall and the final velocity

Explanation:

the mass of solid ball is more than the mass of hollow ball.

According to the third equation of motion

v² = u² + 2gh

As the final velocity v does not depend on the mass of the object, so the final velocity of both the ball is same.

According to the first equation of motion

v = u + gt

As v is same for both the balls, the time is also same for both the balls.

So, they both have same time of fall and final velocity.

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Using software, a simulation of a javelin being thrown both on Earth and on the moon is created. In both cases, the velocity and
mario62 [17]

Horizontal distance covered by a projectile is X = Vix *T

where Vix is the initial horizontal component of velocity and T is time taken by the projectile

Vix = ViCos theta

In question they said that initial velocity and angle is same on earth and moon

so Vix would remains same

now let's see about time taken T

time taken to reach the highest point

Vfy = Viy +gt

at highest point vertical velocity become zero so Vfy =0

0 = Vi Sin theta + gt

t = Vi Sintheta /g

Total time taken to land will be twice of that

On earth

Te= 2t

Te = 2Sinθ/g

on moon g is one-sixth of g(earth)

Tm = 2Sinθ/(g/6)

Tm = 6(2Sinθ/g)

Tm = 6Te

so total time taken by the projectile on moon will be six times the time taken on earth

From first equation X = Vix*T

we can see that X will also be 6 times on moon than earth

so projectile will cover 6 times distance on moon than on earth

4 0
2 years ago
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Answer: Charging.

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2 years ago
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Nodes and antinodes.are part of an _____ wave<br><br> A active <br> B standing
mel-nik [20]
It could be A :) not sure tho
5 0
3 years ago
An isloated point charge produce an electric field with magnitude E at a point 2 m away. At a point 1 m from the charge magnitud
Nina [5.8K]

Answer:

the correct answer is C,      E’= 4E

Explanation:

In this exercise you are asked to calculate the electric field at a given point

         E = k \frac{q}{r^2}

indicates that the field is E for r = 2m

         E = \frac{ k q}{4}                  (1)

the field is requested for a distance r = 1 m

         E ’= k \frac{q}{r'^2}

         E ’= k q / 1

 

from equation 1

         4E = k q

       

we substitute

        E’= 4E

so the correct answer is C

8 0
3 years ago
Describe how a radiation is similar to b- radiation​
Lina20 [59]

Complete question is;

Describe how α-radiation is similar to β-radiation?

Answer:

Explained below

Explanation:

The similarity between both alpha radiation and beta radiation is that in both cases, they both show deflection when they go through electric and magnetic fields. Although alpha deflects towards the negative plate while bets deflects towards the positive plate.

Secondly they both have high speeds. Just that alpha is from the helium nucleus while beta is from electrons.

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