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3 years ago

Which is the correct stem-and-leaf plot for the data set? 11, 10, 49, 36, 35, 34, 11, 32

Mathematics

2 answers:

hram777 [196]3 years ago

5 0

Answer:

The answer is B

Step-by-step explanation:

mihalych1998 [28]3 years ago

5 0

Answer:

The second choice

Step-by-step explanation:

Just make the plot:

1 | 0, 1

2 |

3 | 2, 4, 5, 6

4 | 9

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Does anyone know this?

Darina [25.2K]

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Because you are multiplying two, four times

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3 years ago

The graph below shows a quadratic function f(x) and an absolute value function g(x)

Sophie [7]

Answer:

The x-values that are approximate solution of the equation $f(x) = g(x)$ are $x_{1} \approx -3.5$ and $x_{2}\approx 5$ , respectively.

Step-by-step explanation:

From graph we infer that the x-values that represents a solution to the system of equations corresponds to those values of x in which both functions coincide. As we see, there are two x-values for $f(x) = g(x)$ , which are described below:

$x_{1} \approx -3.5$ and $x_{2}\approx 5$

The x-values that are approximate solution of the equation $f(x) = g(x)$ are $x_{1} \approx -3.5$ and $x_{2}\approx 5$ , respectively.

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4 years ago

Help plz I will give brainliest

HACTEHA [7]

Answer:

i think that it is C

Step-by-step explanation:

if im incorrect i apologize

5 0

3 years ago

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$