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dsp73
3 years ago
9

Give an example of a situation in which you would describe an object's position in

Physics
1 answer:
notka56 [123]3 years ago
8 0
Incomplete question.  Full text is:

"<span>Give an example of a situation in which you would describe an object's position in (a) one-dimension coordinates (b) two-dimension coordinates (c) three-dimension coordinates"

Solution
(a) One dimension example: a man walking along a metal plank. We just need to specify one coordinate, the distance from the beginning of the plank.

(b) Two-dimension example: a ball moving on a circle. In this case, we need two coordinates: (x,y) to specify the position of the ball at every instant, since it is moving on a 2-D plane.

(c) The position of an airplane in the air: in this case we need 3 coordinates, the height, the latitude and the longitude of the airplane.</span>
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A train moves at a constant velocity of 90 km/h. How far will it move in 0.25h?<br>​
Serjik [45]
In 0.25h it will move in 22.5 kilometers.
8 0
3 years ago
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Scientific work is currently underway to determine whether weak oscillating magnetic fields can affect human health. For example
ValentinkaMS [17]

Answer:

2.02672\times 10^{-11}\ V

Explanation:

f = Frequency = 75 Hz

B = Magnetic field = 1\times 10^{-3}\ T

d = Diameter of cell = 7.4\ \mu m

t = Time taken

\omega = Angular frequency

The expression of emf is

E=NAB\omega sin\omega t

Emf is maximum when sin\omega t=1 and N = number of turns = 1

E_m=AB\omega\\\Rightarrow E_m=\pi \left(\frac{d}{2}\right)^2 \times B \times 2\pi\times f\\\Rightarrow E_m=\pi \left(\frac{7.4\times 10^{-6}}{2}\right)^2\times 1\times 10^{-3}\times 2\pi\times 75\\\Rightarrow E_m=2.02672\times 10^{-11}\ V

The maximum emf that can be generated around the perimeter of a cell in this field is 2.02672\times 10^{-11}\ V

4 0
3 years ago
One strategy in a snowball at a high angle over level ground. While your opponent is watching this first snowball, you throw a s
siniylev [52]

Answer:

33°

Explanation:

We are given;

Speed at which both snowballs are thrown; v = 33.2 m/s

Angle at which snowballs are thrown with respect to the horizontal; θ = 57°

Now,we want to find out the angle at which the second snowball should be thrown in order to arrive at the same point as the first.

To calculate this angle, we will use complementary angle concept.

Now, because the target is in the same place, there will be two launch angles that will make the snow ball to be placed on the target.

The is calculated from;θ1 = 45° - (57° - 45°) = 33°

8 0
3 years ago
Which rate indicates the number of children that would be born per woman if she were to live to the end of her child-bearing yea
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Birth Rate would be the rate that indicates the number of children that would be born per woman if she were to live to the end of her child bearing days.
3 0
3 years ago
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This is a two part question:
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Answer:

1. 310 N

2. 310 N

Explanation:

1. Determination of the net force.

Force applied (Fₐ) = 430 N

Force experience (Fₑ) = 120 N

Net force (Fₙ) =?

Fₙ = Fₐ – Fₑ

Fₙ = 430 – 120

Fₙ = 310 N

Hence, the net force acting on the crate is 310 N

2. Determination of the net force.

Force applied (Fₐ) = 375 N

Force of friction (Fբ) = 65 N

Net force (Fₙ) =?

Fₙ = Fₐ – Fբ

Fₙ = 375 – 65

Fₙ = 310 N

Hence, the net force acting on the crate is 310 N.

8 0
2 years ago
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