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dsp73
3 years ago
9

Give an example of a situation in which you would describe an object's position in

Physics
1 answer:
notka56 [123]3 years ago
8 0
Incomplete question.  Full text is:

"<span>Give an example of a situation in which you would describe an object's position in (a) one-dimension coordinates (b) two-dimension coordinates (c) three-dimension coordinates"

Solution
(a) One dimension example: a man walking along a metal plank. We just need to specify one coordinate, the distance from the beginning of the plank.

(b) Two-dimension example: a ball moving on a circle. In this case, we need two coordinates: (x,y) to specify the position of the ball at every instant, since it is moving on a 2-D plane.

(c) The position of an airplane in the air: in this case we need 3 coordinates, the height, the latitude and the longitude of the airplane.</span>
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A student measures the speed of sound by echo destiny classes hands and then measures the time to hear the echo his distance to
777dan777 [17]

Explanation:

∆x=300 m×2

∆t=1.5 s

v=∆x/∆t → v=2×300/1.5 = 400 m/s

6 0
3 years ago
How to find speed with acceleration and distance?
777dan777 [17]
Its a very syplel thing devipe it by distance and boom u shude have it
3 0
4 years ago
A car's bumper is designed to withstand a 6.84 km/h (1.9-m/s) collision with an immovable object without damage to the body of t
PilotLPTM [1.2K]

Answer:

859.07 N

Explanation:

u = Initial velocity = 1.9 m/s

v = Final velocity

s = Displacement = 0.165 m

a = Acceleration

m = Mass = 890 kg

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-1.9^2}{2\times 0.165}\\\Rightarrow a=-10.93\ m/s^2

Force

F=ma\\\Rightarrow F=870\times -10.93\\\Rightarrow F=859.07\ N

The magnitude of the average force on the bumper is 859.07 N

4 0
3 years ago
A conducting coil of 1470 turns is connected to a galvanometer, and the total resistance of the circuit is 56.0 . The area of ea
Damm [24]

Answer:

 B = - 1.51 10⁻⁷ T

Explanation:

For this exercise we can use Faraday's law of induction

          E = - - \frac{d \phi _B}{dt} = - \frac{d (B A cos \theta )}{dt}

           

In this case, they indicate that the normal and the magnetite field are in the same direction, so the angle is zero (cos 0 = 1), they give the area of ​​the loop A = 4.32 10⁻⁴ m² and since we have N = 1470 turns in each one a voltage is induced

          E = - N B A

          B = -E A / N               (1)

we find the induced voltage with ohm's law

         V = i R

where the current is defined by

         i = Q / t

we substitute

          V = Q R / t

 

let's calculate

         V = 9.18 10-3 56.0 / t

We must assume a time normally is t = 1 s

         V = 0.514 V

this is the voltage in the circuit which must be the induced voltage V = E

we substitute in 1

         B = - 0.514 4.32 10⁻⁴ / 1470

         B = - 1.51 10⁻⁷ T

3 0
3 years ago
Robert dropped his new iPhone from his balcony. It hit the ground 3.5 seconds later. What was the height of his balcony?
Lorico [155]

its B. 60 meters

Explanation:

cause I looked up a calculator and solved it

8 0
3 years ago
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