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AURORKA [14]
4 years ago
5

Even though forces are acting on this box, it remains at rest on the table. Which force is represented by vector A.

Physics
2 answers:
diamong [38]4 years ago
8 0

Answer:

C.Static friction

Explanation:

We are given tat a box which is kept on the table.

The box is at rest on the table.

We have to find which force is represented by vector A

We know that

Static friction: it is that force which kept object at rest.It is a type of friction force and  exist  between stationary object and surface on which it is resting.

When some forces acting on the box but the box remain at rest  on the table due to static friction.

The force is represented by vector A is static friction .

Answer:C.Static friction

V125BC [204]4 years ago
4 0

Answer:

Static Friction

Explanation:

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38.4 mol of krypton is in a rigid box of volume 64 cm^3 and is initially at temperature 512.88°C. The gas then undergoes isobari
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Answer:

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Final Pressure second process P_{3} = 1,317 * 10^{10} Pa

Explanation:

Using the Ideal Gases Law yoy have for pressure:

P_{1} = \frac{n_{1} R T_{1} }{V_{1} }

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P is the pressure, in Pa

n is the nuber of moles of gas

R is the universal gas constant: 8,314 J/mol K

T is the temperature in Kelvin

V is the volumen in cubic meters

Given that the amount of material is constant in the process:

n_{1} = n_{2} = n

In an isobaric process the pressure is constant so:

P_{1} = P_{2}

\frac{n R T_{1} }{V_{1} } = \frac{n R T_{2} }{V_{2} }

\frac{T_{1} }{V_{1} } = \frac{T_{2} }{V_{2} }

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T = \frac{P V }{n R }

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\frac{P_{2} V_{2} }{n R } = \frac{P_{3} V_{3} }{n R }

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P_{3} = \frac{P_{2} V_{2}}{V_{3}}

P_{3} = 1,317 * 10^{10} Pa

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