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marysya [2.9K]
3 years ago
6

Easy physics question help.!!!

Physics
2 answers:
Alexus [3.1K]3 years ago
4 0
Try using socratic it is very helpful
stellarik [79]3 years ago
3 0

Answer: This is not easy lol

Explanation:

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HELP ME ASAP!!!! PIC IS DOWN BELOW!
vagabundo [1.1K]
I think it is B Because it sounds like the best choice
7 0
3 years ago
Read 2 more answers
How long (in seconds) does it take a car accelerating at 3.1 m/s2 to go from rest<br> to 51 m/s?
Nesterboy [21]

Answer:

 t  = 16.5s

Explanation:

Given parameters:

Acceleration = 3.1m/s²

Initial velocity  = 0m/s

Final velocity  = 51m/s

Unknown:

Time taken  = ?

Solution:

To solve this problem we need to reiterate that acceleration is the rate of change of velocity with time.

So;

        Acceleration  = \frac{v  - u }{t}  

v is the final velocity

u is the initial velocity

t is the time taken

  So;

       3.1  = \frac{51 - 0}{t}  

    3.1t  = 51

       t  = 16.5s

8 0
3 years ago
A soccer ball is traveling at a velocity of 50 m/s. The kinetic energy of the ball is 500 J. What is the mass of the soccer ball
Savatey [412]
A soccer ball is traveling at a velocity of 50 m/s. The kinetic energy of the ball is 500 J.The mass of the soccer ball is 0.4 kgs. This answer is derived from the formula K=1/2 MV^2.So velocity and kinetic energy are given from that mass of the ball is calculated.By substituting the values 500=1/2*M*50*50 which gives M=0.4 Kgs.<span>
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4 0
3 years ago
Read 2 more answers
A mass is placed at the end of a spring. It has starting velocity of V &amp; allowed to oscillate freely. If the mass has a star
LiRa [457]

Answer:

Equation for SHM can be written

V = w A cos w t        where w is the angular frequency and the velocity is a                                         maximum at t = 0

V1 = w1  A cos w1 t

V2 = w2 A cos w2 t

V2 / V1 = w2 / w1     since cos X t = 1 if t = zero

V2 / V1 = 2 pi f2 / (2 pi f1) = f2 / f1 = T1 / T2

If the velocity is twice as large the period will be 1/2 long

8 0
3 years ago
In a physics lab, Asha is given a 10.7 kg uniform rectangular plate with edge lengths 67.3 cm by 53.5 cm . Her lab instructor re
Leya [2.2K]

Answer:

I=2.6363\ kg.m^2

Explanation:

Given:

dimension of uniform plate, (0.673\times 0.535)\ m^2

mass of plate, m=10.7\ kg

Now we find the moment of inertia about the center of mass of the rectangular plate is given as:

I_{cm}=\frac{1}{12} \times m(L^2+B^2)

where:

L= length of the plate

B= breadth of the plate

I_{cm}=\frac{1}{12} \times 10.7\times(0.673^2+0.535^2)

I_{cm}=0.6591\ kg.m^2

We know that the center of mass of the rectangular plane is at its geometric center which is parallel to the desired axis XX' .

Now we find the distance between the center of mass and the corner:

s=\frac{\sqrt{ (0.673^2+0.535^2)}}{2}

s=0.4299\ m

Now using parallel axis theorem:

I=I_{cm}+m.s^2

I=0.6591+10.7\times 0.4299^2

I=2.6363\ kg.m^2

6 0
3 years ago
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