Answer:
Explanation:
spring constant, K = 13.1 N/m
22 oscillations in 20 seconds
time taken to complete one oscillation is called time period.
T = 20 / 22 second = 0.909 seconds
(a) let m be the mass.
The formula for the time period is



m = 0.275 kg
(b) maximum speed, v = ω A = 2π A / T
v = ( 2 x 31.4 x 0.1) / 0.909
v = 0.691 m/s

Explanation:
Natural length of a spring is
. The spring is streched by
. The resultant energy of the spring is
.
The potential energy of an ideal spring with spring constant
and elongation
is given by
.
So, in the current problem, the natural length of the spring is not required to find the spring constant
.

∴ The spring constant of the spring = 
Answer:
doubled
Explanation:
F=ma1----------(1)
2F = ma2-------(2)
Divide 2nd equation by 1st one
we get a1×2=a2
Answer:
F-ma
Explanation:
If you are speaking of objects like satellites, etc. then their mass is much less than that of the Earth. A good approximation is Newton's first law of motion:
Force
=
Mass × Acceleration
often written:
F
=
m
a
The gravitational force is the same between the Earth and the object - only the mass differs. So the acceleration is inversely proportional to the mass.
At the most distant point, the size of the speed is zero (0 m/s). This is a direct result of preservation of vitality. PE = KE. The most distant far from the harmony position is the maximum PE. Hence it can have no KE. No KE implies no speed since KE = .5mv2