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romanna [79]
3 years ago
12

How often would you push someone on a swing to create a frequency of .4 hertz

Physics
1 answer:
Wewaii [24]3 years ago
4 0
The unit "Hertz" means "per second".

Anything happening with a frequency of 0.4 Hz is happening 0.4 per second.

Technically, you must push the swing 0.4 times per second.
But since it's very hard to push 0.4 of one time, you have to be
able to figure out that you should push once every 2.5 seconds.

     (1 push / 2.5 sec)  =  (1/2.5) push/sec  =  0.4 per sec  =  0.4 Hz .
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A skater starts on a ramp 5 m above the ground. They have a mass of 45 kg. What is their gravitational potential energy?
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Answer:

2205J

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Read 2 more answers
The platform height for Olympic divers is 10 m. A 60 kg diver steps off the platform to begin his dive.
azamat

Answer:

a) Ep = 5886[J]; b) v = 14[m/s]; c)   W = 5886[J]; d) F = 1763.4[N]

Explanation:

a)

The potential energy can be found using the following expression, we will take the ground level as the reference point where the potential energy is equal to zero.

E_{p} =m*g*h\\where:\\m = mass = 60[kg]\\g = gravity = 9.81[m/s^2]\\h = elevation = 10 [m]\\E_{p}=60*9.81*10\\E_{p}=5886[J]

b)

Since energy is conserved, that is, potential energy is transformed into kinetic energy, the moment the harpsichord touches water, all potential energy is transformed into kinetic energy.

E_{p} = E_{k} \\5886 =0.5*m*v^{2} \\v = \sqrt{\frac{5886}{0.5*60} }\\v = 14[m/s]

c)

The work is equal to

W = 5886 [J]

d)

We need to use the following equation and find the deceleration of the diver at the moment when he stops his velocity is zero.

v_{f} ^{2}= v_{o} ^{2}-2*a*d\\where:\\d = 2.5[m]\\v_{f}=0\\v_{o} =14[m/s]\\Therefore\\a = \frac{14^{2} }{2*2.5} \\a = 39.2[m/s^2]

By performing a sum of forces equal to the product of mass by acceleration (newton's second law), we can find the force that acts to reduce the speed of the diver to zero.

m*g - F = m*a

F = m*a - m*g

F = (60*39.2) - (60*9.81)

F = 1763.4 [N]

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3 years ago
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