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navik [9.2K]
3 years ago
14

Discuss how the move over law applies to this is situation and your responsibility as a driver

Physics
2 answers:
lesya [120]3 years ago
6 0

Answer:

  • There are certain rules which are required to be obeyed by any person who is  on the road while driving any sort of vehicle i.e a bike, cycle or a sedan etc. Each road is divided in to three main parts the emergency line, the high speed and the low speed line.
  • So, as according to the mover over law if a driver at first is traveling by the emergency line and there comes any sort of government , police, any two truck, fire-brigade or an ambulance he or she must vacate that emergency line for the mentioned vehicles as, that are termed to be treated more differently just because of there work nature.

Liono4ka [1.6K]3 years ago
3 0

Answer:

The two reasons are as given.

Explanation:

  • The move over law is defined for safety of all the personal involved. This includes the officer, the driver and the person being pulled over. As a driver pulling over helps the officer control the situation with the pulled over person
  • If it is an ambulance or a firetruck with their sirens on it means they are having to get to an emergency so for the others safety as well as for the emergency to save lives pulling over is required so that the emergency vehicle can move further.

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What is the average power output of an athlete who can life 9.0 * 10^2 kg 2.5 m in 2.0 s?
eduard

Answer:

Average power output of athlete = 11025 Watts

Explanation:

Work done is defined as the product of force applied and the displacement perpendicular to the force.

Work = Force\times Displacement

Power is defined as work done per unit time.

Power = \frac{Work done}{Time}

Here the person lifts 900 kg.

Height = 2.5 m

Time interval = 2 seconds

Force = weight \times gravity

          = 900 \times 9.8

          = 8820 N

Work done = Force\times Displacement

                   = 8820 \times 2.5

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Power = \frac {22050}{2}

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3 0
3 years ago
Although we have discussed single-slit diffraction only for a slit, a similar result holds when light bends around a straight, t
user100 [1]

Answer:

The width of the strand of hair is   1.96 10⁻⁵ m

Explanation:

For this diffraction problem they tell us that it is equivalent to the diffraction of a single slit, which is explained by the equation

<h3>       a sin θ =±  m λ </h3><h3 />

Where the different temrs are: “a” the width of the hair, λ the wavelength, θ the angle from the center, m the order of diffraction, which is the number of bright rings (constructive diffraction)  

We can see that the diffraction angle is missing, but we can find it by trigonometry, where L is the distance of the strand of hair to the observation screen and "y" is the perpendicular distance to the first minimum of intensity

        L = 1.25 m 100 cm/1m   = 125 cm

       y = 5.06 cm  

      Tan θ = y/L

      Tan θ = 5.06/125

      θ = tan⁻¹ ( 0.0405)

      θ =  2.32º

With this data we can continue analyzing the problem, they indicate that they measure the distance to the first dark strip, thus m = 1

     a = m λ / sin θ

     a = 1 633 10⁻⁹ 1.25/sin 2.3

     a = 1.96 10⁻⁵ m  

     a = 0.0196 mm

The width of the strand of hair is   1.96 10⁻⁵ m

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If a negative object is used to charge a neutral object, then both objects become charged negatively. In order for the neutral sphere to become negative, it must gain electrons from the negatively charged rod. A metal sphere is electrically neutral. It is touched by a positively charged metal rod.

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