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AlexFokin [52]
3 years ago
5

In a science fiction novel two enemies, Bonzo and Ender, are fighting in outer spce. From stationary positions, they push agains

t each other. Bonzo flies off with a velocity of +2.2 m/s, while Ender recoils with a velocity of -2.6 m/s. Determine the ratio mBonzo/mEnder of the masses of these two enemies.
Physics
1 answer:
Hoochie [10]3 years ago
8 0

Answer:

\frac{m_B}{m_E}=1.18

Explanation:

m_B = Mass of Bonzo

m_E = Mass of Ender

u_B = Initial Velocity of Bonzo = 2.2 m/s

u_E = Initial Velocity of Ender = -2.6 m/s

From conservation of linear momentum

m_Bu_B=m_Eu_E\\\Rightarrow \frac{m_B}{m_E}=\frac{u_E}{u_B}\\\Rightarrow \frac{m_B}{m_E}=\frac{2.6}{2.2}\\\Rightarrow \frac{m_B}{m_E}=1.18

\therefore \frac{m_B}{m_E}=1.18

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A 4 kg bowling ball rolls at a speed of 5 m/s on the roof of a building that is 30 meters tall. What is its kinetic energy?
klasskru [66]

ans: B

Kinetic energy = \frac{1}{2} mv^{2}

= \frac{1}{2} (4)(5^{2} )

= 50J

ps. the height will only affect its potential energy, not kinetic.

3 0
3 years ago
A kite is hovering over the ground at the end of a straight 38-m line. the tension in the line has a magnitude of 17 n. wind blo
postnew [5]

Let the tension in the thread will be at angle theta

now by force balance in  x and y directions we can say

17 cos\theta = 18 cos60

17 cos\theta = 9

\theta = 58.03 degree

now for the height of the kite we can use

h = L sin\theta

h = 38 sin58.03

h = 32.23 m

<em>so it will be at height 32.23 m from ground</em>

3 0
3 years ago
Power is work done over a what?
melomori [17]
No the answer is energy 
4 0
3 years ago
the net external force on the 24-kg mower is stated to be 51 N. If the force of friction opposing the motion is 24 N, what force
-Dominant- [34]

Answer:

PART A)

External force will be 75 N

PART B)

distance moved will be 1.125 m

Explanation:

PART A)

Given that net force on the mower is

F_{net} = 51 N

now we also know that friction force due to ground is given as

F_f = 24 N

now we have

F_{net} = F_{ext} - F_f

51 = F_{ext} - 24

F_{ext} = 75 N

so external force will be 75 N

PART B)

deceleration due to friction when external force is removed from it

a = \frac{F_f}{m}

a = \frac{24}{24} = 1 m/s^2

now we can find the distance by kinematics

v_f^2 - v_i^2 = 2 a d

0 - 1.5^2 = 2(-1)d

d = 1.125 m

so the distance moved will be 1.125 m

6 0
3 years ago
Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 20 cm apart. The sound
Sophie [7]

Answer:

a. Wavelength = λ = 20 cm

b. Next distance of maximum intensity will be 40 cm

Explanation:

a. The distance between the two speakers is 20cm. SInce the intensity is maximum which refers that we have constructive interference and the phase difference must be an even multiple of π and equivalent path difference is nλ.

Now when distance increases upto 30 cm between the speakers, the sound intensity becomes zero which means that there is destructive interference and equivalent path is now increased from nλ to nλ + λ/2.

This we get the equation:

(nλ + λ/2) - nλ = 30-20

λ/2 = 10

λ = 20 cm

b. at what distance, sound intensity will be maximum again.

For next point calculation for maximum sound intensity, the path difference must be increased (n+1) λ. The distance must increase by λ/2 from the point of zero intensity.

= 30 + λ/2

= 30 + 20/2

=30+10

=40 cm

7 0
3 years ago
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