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3 years ago

Explainnnnnnnn plzzzzz!

Mathematics

1 answer:

miskamm [114]3 years ago

7 0

Answer:

i and iv...................

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V=2.5(6.4−t)

Alja [10]

Answer:

6.4 minutes ( or 6 minutes and 24 seconds)

Step-by-step explanation:

Filling up the jug means the empty space is 0, hence V = 0.

<em>We plug in 0 into V and solve for t to get the time required to fill it up:</em>

$V=2.5(6.4-t)\\0=2.5(6.4-t)\\0=16-2.5t\\2.5t=16\\t=\frac{16}{2.5}\\t=6.4$

Hence it will take 6.4 minutes to fill up the jugs.

<u>Note:</u> 0.4 minutes in seconds is $0.4*60=24$ seconds

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3 years ago

In the diagram, figure I is a square, and figures II and III are equilateral triangles. What is the value of x?

baherus [9]

Answer:

Step-by-step explanation:

5 0

3 years ago

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What’s the percent on 1/2cents

ss7ja [257]

The percent is 0.5 or 0.50

4 0

3 years ago

Please help me with the question

mars1129 [50]

(i) The mean is

$\displaystyle E(X) = \sum_x x \, P(X = x) \\\\ E(X) = 1\cdot0.175 + 2\cdot0.315 + 3\cdot0.211 + 4\cdot0.092 + 5\cdot0.207 \\\\ \boxed{E(X) = 2.839}$

The variance is

$V(X) = E((X - E(X))^2) = E(X^2) - E(X)^2$

Compute the second moment $E(X^2)$ :

$\displaystyle E(X^2) = \sum_x x^2 \, P(X = x) \\\\ E(X) = 1^2\cdot0.175 + 2^2\cdot0.315 + 3^2\times0.211 + 4^2\times0.092 + 5^2\times0.207 \\\\ E(X^2) = 9.997$

Then the variance is

$\boxed{V(X) \approx 1.9171}$

(ii) For a random variable $Z=aX+b$ , where $a,b$ are constants, we have

$E(Z) = E(aX+b) = E(aX) + E(b) = a E(X) + b$

and

$V(Z) = E((aX+b)^2) - E(aX+b)^2 \\\\ V(Z) = E(a^2 X^2 + 2ab X + b^2) - (a E(X) + b)^2 \\\\ V(Z) = a^2 (E(X^2) - E(X)^2) \\\\ V(Z) = a^2 V(X)$

Then for $Y=\frac{X+3}2$ , we have

$E(Y) = \dfrac12 E(X) + \dfrac32 \\\\ \boxed{E(Y) = 2.918}$

$E(Y^2) = E\left(\left(\dfrac{X+3}2\right)^2\right) = \dfrac14 E(X^2) + \dfrac32 E(X) + \dfrac94 \\\\ \boxed{E(Y^2) \approx 9.0028}$

3 0

2 years ago

Four consecutive Integers of 1738

Oksi-84 [34.3K]

Answer:

1739, 1740, 1741, 1742

Step-by-step explanation:

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3 years ago

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