A.) P(t) = 130t - 0.4t^4 + 1200
The population is maximum when P'(t) = 0
P'(t) = 130 - 1.6t^3 = 0
1.6t^3 = 130
t^3 = 81.25
t = ∛81.25 = 4.3 months.
Maximum population P(t)max = 130(4.3) - 0.4(4.3)^4 + 1200 = 1,622
b.) The rabbit population will disappear when P(t) = 0
P(t) = 130t - 0.4t^4 + 1200 = 0
t ≈ 8.7 months
53: 800 and 900
54: 700 and 800
55: 500 and 600
56: 2,771,100 and 2,771,200
57: 90,120,000 and 90,120,100
58: 631,900 and 632,000
59: 93,300 and 93,400
60: 200 and 300
61: 900 and 1000
62: 39,576,700 and 39,576,800
63: 24,900 and 25,000
64: 471,100 and 471,200
Answer:
Step-by-step explanation:
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Answer
D
Step-by-step explanation:
y=2x+15
7=2(-4)+15
7=15-8
7=7
7x+2y=-14
7(-4)+2(7)=-14
-28+14=-14
-14=-14
Answer:
-12
Step-by-step explanation:
Take the variables into the equation:
-|(-3)-4|+(-5)
The negative absolute value of -3 and 4 is -7.
-7+(-5)= -12